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Gennadij [26K]
1 year ago
12

What is the net force in this image?

Physics
1 answer:
9966 [12]1 year ago
6 0

Net force on the image is 0 Newton.

<h3>What is force?</h3>

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Net upward force is balanced by net downward force so net force is zero.

Net force on the image is 0 Newton.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ1

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Expressing Experimental Error If the accepted value of π is 3.1416, what are the fractional error and the percent error of the e
LUCKY_DIMON [66]

Answer:

1) Δx  = 0.16 m / s² ,   Δx = 9.72-9.8 = 0.08 m / s²

2)  e% = 1.63% , ,   e% = 0.816%

3)           1e% = 0.04

Explanation:

The fractional error in a quantity is the absolute error between the accepted value of the quantity and the percentage error is the fractional error per 100

In this case, it is not indicated which is the measured experimental value of pi, suppose that a value of 3.142 is measured

fractional error

                 e = (ax - ax_average) / x_average

                 e = (3.142 - 3.1416) / 3.1416

                 e = 1.27 10⁻⁴

the percentage error is

                 % = e 100

                 % = 1.27 10-4 100

                 % = 1.27 10⁻²%

1) Δx = 9.96-9.8 = 0.16 m / s²

            Δx = 9.72-9.8 = 0.08 m / s²

2) the percentage difference

 x = 9.96 m / s2

             e% = (9.96 - 9.80) / 9.80 100

             e% = 1.63%

x = 9.72 m / s2

             e% = (9.72 -9.80) / 9.80 100

              e% = 0.816%

3) the mean value is

                x_average = (x1 + x2) / 2

               x_average = (9.96 + 9.72) / 2

               x_average = 9.84 m / s2

               e% = (9.84 - 9.80) / 9.80 100

             1e% = 0.04

7 0
3 years ago
A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9
Black_prince [1.1K]

Answer:

C = 46.891 \mu F

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

s = \frac{P}{P.F} < COS^{-1} 0.65

S = \frac{1250}{0.65} < 49.45

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]

solving for Q_{new}

Q_{new} = P tan [cos^{-1} P.F new]

Q_{new} = 1250 [tan[cos^{-1}0.9]]

Q_{new} = 605.40 VARS

Q_C = Q - Q_{new}

Q_C = 1461 - 605.4 = 855.6 vars

Q_C = \frac[v_{rms}^2}{xc} =v_{rms}^2 \omega C

C = \frac{Q_C}{ v_{rms}^2 \omega}

C = \frac{855.6}{220^2 \times 2\pi \times 60}

C = 4..689 \times 10^{-5} Faraday

C = 46.891 \mu F

6 0
4 years ago
Name the processes of going (a) from a solid to a gas and (b) from a gas to a solid.
marissa [1.9K]
The answer to the first one is sublimation.
8 0
3 years ago
Let's say you have a plot for Pendulum experiment. Let's assume g for this experiment was measured (from the slope of the plot)
Gemiola [76]

Answer:

0.0052 m

Explanation:

T^2=0.021\ s^2

g = Acceleration due to gravity = 9.78 m/s²

Time period

T=2\pi \sqrt{\frac{L}{g}}\\\Rightarrow T^2=4\pi^2 \frac{L}{g}

\Rightarrow L=\frac{T^2g}{4\pi^2}

\Rightarrow L=\frac{0.021\times 9.78}{4\pi^2}\\\Rightarrow L=0.0052\ m

The length of the pendulum is 0.0052 m

3 0
3 years ago
A bowling ball traveling with constant speed hits pins at the end of a bowling lane 16.5m long. The bowler hears the sound of th
sweet-ann [11.9K]

Answer: The speed of the ball is 7.64 m/s.

Explanation:

The distance between the player and the pins is 16.5m

if the velocity of the ball is V, then the time in which the ball reaches the pins is:

T = 16.5/V

Now, after this point, the sound needs

T' = 16,5/340 = 0.049 seconds to reach the player, this means that the time in that the ball needs to reach te pins is:

2.65 s - 0.49s = 2.16s

Then we have:

T = 2.16s = 16.5/V

V = 16.5/2.16 m/s = 7.64 m/s

7 0
3 years ago
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