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3 years ago

12

Let's say you have a plot for Pendulum experiment. Let's assume g for this experiment was measured (from the slope of the plot)

to be 9.78 [ms-2. The vertical intercept, however, is 0.021 [s2]. What might this translate to for a measurement of the length offset systematic in all the length measurements?

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

0.0052 m

Explanation:

$T^2=0.021\ s^2$

g = Acceleration due to gravity = 9.78 m/s²

Time period

$T=2\pi \sqrt{\frac{L}{g}}\\\Rightarrow T^2=4\pi^2 \frac{L}{g}$

$\Rightarrow L=\frac{T^2g}{4\pi^2}$

$\Rightarrow L=\frac{0.021\times 9.78}{4\pi^2}\\\Rightarrow L=0.0052\ m$

The length of the pendulum is 0.0052 m

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In this situation the skater has two values of momentum:

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Where:

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So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

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Read 2 more answers

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To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:

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$lA = 1.233*10^{-7} m^3$ (1)

We know that,

$\frac{l}{A} = \frac{R}{\gamma}$

$\frac{l}{A}= \frac{0.390\Omega}{1.7*10^{-8}\Omega m}$

$\frac{l}{A} = 2.2941*10^7 m^{-1}$ (2)

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$l^2 = (1.233*10^{-7})( 2.2941*10^7)$

$l^2 = 2.8286m^2$

$l =\sqrt{2.8286m^2}$

$l = 1.68m$

Therefore the length of the wire is 1.68m

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