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wariber [46]
3 years ago
12

Let's say you have a plot for Pendulum experiment. Let's assume g for this experiment was measured (from the slope of the plot)

to be 9.78 [ms-2. The vertical intercept, however, is 0.021 [s2]. What might this translate to for a measurement of the length offset systematic in all the length measurements?
Physics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

0.0052 m

Explanation:

T^2=0.021\ s^2

g = Acceleration due to gravity = 9.78 m/s²

Time period

T=2\pi \sqrt{\frac{L}{g}}\\\Rightarrow T^2=4\pi^2 \frac{L}{g}

\Rightarrow L=\frac{T^2g}{4\pi^2}

\Rightarrow L=\frac{0.021\times 9.78}{4\pi^2}\\\Rightarrow L=0.0052\ m

The length of the pendulum is 0.0052 m

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A 1kg cart slams into a stationary 1kg cart at 2 m/s. The carts stick together and move forward at a speed of 1 m/sl. Determine
finlep [7]

Answer:

No, it is not conserved

Explanation:

Let's calculate the total kinetic energy before the collision and compare it with the total kinetic energy after the collision.

The total kinetic energy before the collision is:

K_i = K_1 + K_2 = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2=\frac{1}{2}(1 kg)(2 m/s)^2+\frac{1}{2}(1 kg)(0)^2=2 J

where m1 = m2 = 1 kg are the masses of the two carts, v1=2 m/s is the speed of the first cart, and where v2=0 is the speed of the second cart, which is zero because it is stationary.

After the collision, the two carts stick together with same speed v=1 m/s; their total kinetic energy is

K_f = \frac{1}{2}(m_1+m_2)v^2=\frac{1}{2}(1 kg+1kg)(1 m/s)^2=1 J

So, we see that the kinetic energy was not conserved, because the initial kinetic energy was 2 J while the final kinetic energy is 1 J. This means that this is an inelastic collision, in which only the total momentum is conserved. This loss of kinetic energy does not violate the law of conservation of energy: in fact, the energy lost has simply been converted into another form of energy, such as heat, during the collision.

3 0
3 years ago
Which type of friction keeps a pile of rocks from falling apart?
const2013 [10]
The answer is static friction. This is the friction that involves objects that do not move.
6 0
3 years ago
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find the rate of positive acceleration of an automobile which went from a complete stop to a velocity of 30 meters per second in
maks197457 [2]

Answer:

3 m/s^2

Explanation:

acceleration= Change in velocity/time

= 30-0 / 10

= 30/10

=3 m/s^2

3 0
2 years ago
An archer shoots an arrow with a velocity of 45.0m/s at an angle of 50.0degrees with the horizontal.An assistant standing on the
garri49 [273]

Answer:

a) u = 30.29 m/s

b) t = 2.09 s

Explanation:

given,

velocity = 45 m/s

angle (θ) = 50°

horizontal velocity = 45 cos 50°

time taken to reach 150 m.

times = \dfrac{150}{45 cos 50^0}

t  =  5.19 s

a) height of arrow

s = u t +\dfrac{1}{2}gt^2

s = v sin \theta \times t+\dfrac{1}{2}gt^2

s = 45 sin 50^0 \times 5.19 -\dfrac{1}{2}\times 9.81\times 5.19^2

s = 46.78 m

v² - u² = 2 g s

u² = 2 × 9.81 × 46.78

u = 30.29 m/s

b) time taken by the apple = \dfrac{u}{g}=\dfrac{30.29}{9.81}

                                             = 3.09 s

time after which it has to be thrown = 5.19-3.09 = 2.1 s

5 0
2 years ago
Electrically charged particles are found primarily in
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Answer:

the ionosphere

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