Answer: If both gases undergo the same entropy then more heat is added to gas a because the entropy of the gas a is less than the entropy of the gas b.
Explanation:
Entropy is defined as the degree of randomness. When the temperature of the gas increases then the entropy of gas also increases.
In the given problem, Quantity a of an ideal gas is at absolute temperature t, and a second quantity b of the same gas is at absolute temperature 2t.
Heat is added to each gas, and both gases are allowed to expand isothermally. It means that the volume is constant during this process.
If both gases undergo the same entropy then more heat is added to gas a because the entropy of the gas a is less than the entropy of the gas b. If the heat is added then there will be more entropy.
Answer:
4.4 MJ
Explanation:
We are given that an automobile with an internal combustion engine converts the potential energy of gasoline into kinetic energy of the moving piston.
1 kg of gasoline gives energy=44 MJ.
Average internal combustion engine =10 % efficient
We have to find how much potential energy is converted into energy to run the pistons.
10% of 44 =
Since 10% is efficient of internal combustion.
Therefore, 4.4 MJ potential energy is converted into energy to run the pistons.
Answer:
h= 43.07 m
Explanation:
<u>Given:</u>
Vi = 15 m/s, Vf= 0m/s, t = 2s, a=g=9.8 m/s²
<u>To Find:</u>
height of the clip h= ?m
<u>Solution:</u>
Since it is thrown horizontally an angle of 0°, so Viy = Viy sin 0° = 0 m/s
and Vix = Vix cos 0° = 15 m/s
<u>For Horizontal </u>
h = 0 m, ax = 0m/s and Vix = 15 m/s
so h = h₀ + Vix t + 1/2 a t²
⇒ h₀ = 30 m (Horizontal distance)
<u>For vertical</u>
Viy = 0m/s, h= ? m, a =g=9.8 m/s²
h = h₀ + Viy t + 1/2 a t²
h = 30m + 0 + 1/2 (9.8 m/s² × 2²)
h = 30 + 16.07
h= 43.07 m
Gravitational potential energy :)