Volume of 14.00g of nitrogen at 5.64atm and 315k

Chemistry

1 answer:

VikaD [51]6 months ago

4 0

The volume of a 14.00g of nitrogen at 5.64atm and 315K is 4.59L.

<h3>How to calculate volume?</h3>

The volume of an ideal gas can be calculated using the following ideal gas equation formula;

PV = nRT

Where;

P = pressure (atm)
V = volume (L)
n = number of moles
R = gas law constant
T = temperature

An ideal gas is a hypothetical gas, whose molecules exhibit no interaction, and undergo elastic collision with each other and with the walls of the container.

The number of moles in 14g of nitrogen can be calculated as follows:

moles = 14g ÷ 14g/mol = 1mol

5.64 × V = 1 × 0.0821 × 315

5.64V = 25.86

V = 25.86 ÷ 5.64

V = 4.59L

Therefore, 4.59L is the volume of the gas

Learn more about volume at: brainly.com/question/12357202

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A tank holds 6.90 m3 of water. What is the volume in ft3? (3.28 ft = 1 m, Remember significant figures, but this answer does not

AleksAgata [21]

Volume of tank = $6.9 m^{3}$ (given)

Since, $1 m = 3.28 ft$

So,

$1 m^{3} = 35.287 ft^{3}$

For $6.9 m^{3}$ :

$6.9\times 35.287 ft^{3} = 243.4803 ft^{3}$

The significant rule for multiplication, states that the number of significant figures in the answer obtained by multiplication is determined by the value with the lowest number of significant digits.

Since, the minimum number of decimal places in the above multiplication operation is 1 so, the final result must be upto 1 decimal place only.

$243.4803 ft^{3} \simeq 243.5 ft^{3}$