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Blizzard [7]
3 years ago
12

In the example in the lesson, 0.10 mole of sodium chloride or magnesium chloride or aluminum chloride was added to one liter of

water. How many moles of each chloride are in one milliliter of the respective solutions?
Chemistry
1 answer:
Elza [17]3 years ago
4 0

Answer:

1x10⁻⁴ moles of Cl⁻ in NaCl solution

2x10⁻⁴ moles of Cl⁻ in MgCl₂ solution

3x10⁻⁴ moles of Cl⁻ in AlCl₃ solution

Explanation:

Let's produce the reactions of each salt

NaCl  → Na⁺ +  Cl⁻

0.1 m                 0.1m

MgCl₂ → Mg²⁺  +  2Cl⁻

0.1m                      0.2m

AlCl₃ → Al³⁺  +  3Cl⁻

0.1 m                 0.3m

0.1, 0.2 and 0.3 are the moles of each chloride in each solution and this moles are added to one liter of solvent.

1 L = 1000mL

Let's prepare the rule of three for each

1000 mL ____ 0.1 m ____ 0.2 m _____ 0.3m

1 mL______ 1x10⁻⁴ m ___ 2x10⁻⁴ m _____ 3x10⁻⁴ m

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7 0
3 years ago
If you add 4.00 mL of pure water to 6.00 mL of 0.750 M NaCl solution, what is the concentration of sodium chloride in the dilute
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Answer:

D) 0.450 M

Explanation:

Given data

  • Initial volume (V₁): 6.00 mL
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We can determine the final concentration using the dilution rule.

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C₂ = C₁ × V₁/V₂

C₂ = 0.750 M × 6.00 mL/10.0 mL

C₂ = 0.450 M

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Explanation:

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