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Nastasia [14]
2 years ago
6

Please help me with this Beer Lambert Law Explanation

Chemistry
1 answer:
tino4ka555 [31]2 years ago
5 0

Answer:

The Beer–Lambert law, also known as Beer's law, the Lambert–Beer law, or the Beer–Lambert–Bouguer law relates the attenuation of light to the properties of the material through which the light is travelling.

Explanation:

Please Mark as brainliest

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What phases can carbon dioxide exist?​
Oliga [24]

Answer:

Carbon dioxide is a gas at room temperature

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3 years ago
What is electronic confriguration​
nataly862011 [7]

Answer:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below.

Explanation:

3 0
3 years ago
When Mrs. Green describes the physical properties of matter she said that physical properties often concern changes in state. On
dedylja [7]

Properties of matter can be broadly classified into two categories:

-Physical properties, these usually involve a change in the state of matter

-Chemical properties. these involve a change in the chemical composition of matter.

Now, physical properties can be further classified as:

Extensive: these depend on the amount of the substance, eg: mass, volume  

Intensive: these do not depend on the amount of the substance eg: density, color, melting point, boiling point

A physical property that does not describe a change in state is color. For example: copper sulfate is a compound which is a blue in color. Thus, color provides information which describes the appearance of matter. In contrast, properties like melting or boiling point suggests a change in the state of the substance.


3 0
3 years ago
Look at this picture and please help
Monica [59]

Answer : The kinetic energy will be 24 J.

Explanation : Given,

Mass of marble = 3 kg

Velocity of a marble = 4 m/s

Formula used to calculate the kinetic energy is:

K.E=\frac{mv^2}{2}

where,

K.E = kinetic energy

m = mass

v = velocity

Now putting all the given values in this formula, we get:

K.E=\frac{3kg\times (4m/s)^2}{2}

K.E=24kg.m^2/s^2=24J            (1J=1kg.m^2/s^2)

Therefore, the kinetic energy will be 24 J.

3 0
3 years ago
A tank has a volume of 0.1 m3 and is filled with He gas at a pressure of 5 x 106 Pa. A second tank has a volume of 0.15 m' and i
GarryVolchara [31]

Answer:

P=5.6*10^{6} Pa

Explanation:

Consider that, as the system is adiabatic, U_{1}= U_{2} where U1 and U2 are the internal energies before the process and after that respectively.

Consider that: U=H-PV, and that the internal energy of the first state is the sum of the internal energy of each tank.

So, H_{1}-P_{1}V_{1}=H_{2}-P_{2}V_{2}\\H_{1}^{A} -P_{1}^{A}V_{1}^{A}+H_{1}^{B} -P_{1}^{B}V_{1}^{B}=H_{2}-P_{2}V_{2}

Where A y B are the tanks. The enthalpy for an ideal gas is only function of the temperature, as the internal energy is too; so it is possible to assume: H_{1}=H_{2}\\H_{1}^{A}+H_{1}^{B} =H_{2}

So, P_{1}^{A}V_{1}^{A}+P_{1}^{B}V_{1}^{B}=P_{2}V_{2}

Isolating P_{2},

P_{2}=\frac{P_{1}^{A}V_{1}^{A}+P_{1}^{B}V_{1}^{B}}{V_{2}}

V_{2}=V_{1}^{A}+V_{1}^{B}=0.25m^{3}

So,

P_{2}=\frac{5000000*0.1+6000000*0.15}{0.25}=5600000Pa=5.6*10^{6} Pa

5 0
3 years ago
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