Answer:
2
Step-by-step explanation:
I've answered your other question as well.
Step-by-step explanation:
Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.
Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3
⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab
Substituting a=sin2(x) and b=cos2(x), we have:
sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)
Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:
sin6(x)+cos6(x)=1−3sin2(x)cos2(x)
From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)
Meaning the expression can be rewritten as:
sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)
Answer:
16 : 28
Step-by-step explanation:
If 12 out of the 28 pupils are female, we can calculate the number of males by subtracting the number of females from the total number of pupils.
28 - 12 = 16
So, there are 16 males in the class. Now, we know that the ratio of males : total is 16 : 28.
I hope this helps! Have a lovely day!! :)
(brainliest is much appreciated!!)
Answer:
x = 8
y = 11
Step-by-step explanation:
Total small box weight = 50x [x being the number of small boxes]
Total large box weight = 80y [y being the number of large boxes]
Total boxes = x+y = 19
Total weight = 1280
<em>Determine x and y.</em>
<u>You know 2 equations. One for weight and another for number of boxes each.</u>
<u>Rewrite second equation:</u>
x+y=19
y=19-x
<u>You have to plug in one into another.</u>
1280 = 50x + 80(19-x)
<u>Solve for x</u>
1280 = 50x + 1520 - 80x
-240 = -30x
x = 8
<u>Solve for y by plugging in x into one of the equations:</u>
8+y = 19
y = 11
Simple interest,
FV=P(1+ni)
FV=future value=2500
P=present value, invested amount
n=number of years, =3
i=annual interest rate, =0.095
2500=P(1+3(0.095))
Solve for P.
