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topjm [15]
1 year ago
8

What is the logarithmic function of the graph? show work

Mathematics
1 answer:
tatiyna1 year ago
6 0

If the function of the logarithmic graph is written as

y=\log _ax^b

Since the graph has been shifted to the right from the origin by 5 units

Then

y=b\log _a(x-5)

a is base, b is coefficient, y and x are coordinates on the line

Taking a point on the line, say (21, 2)

x= 21 and y = 2

\begin{gathered} y=\text{ }\log _a(x-5)^b \\ 2\text{ = }\log _a(21-5)^b \\ a^2=(16)^b \\ (a^2)^1=(4^2)^b \\ \text{Equating the base and the power} \\ a\text{ = 4 and b= 1} \end{gathered}

If the base is 4 and the coefficient is 1

The logarithmic function of the graph is

y=\text{ }\log _4(x-5)

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Which of the following lines is not parallel to the graph of y = 3x + 9?
storchak [24]

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2 years ago
How to solve this equation (-14+3/2b)-(1+2/8b) step by step<br> please thank you
zepelin [54]
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5 0
3 years ago
What is the distance between (−5,−4) and (-6,4)?
Helga [31]

The distance formula is:  d  =  sqrt( (x2 - x1)2 + (y2 - y1)2 )

 

For this problem, let (-5, -4) be the "first" point, so  x1 = -5  and  y2 = -4

                      and let (-6, 4) be the "second" point, so  x2 = -6  and  y2 = 4.

 

Then:  d  =  sqrt( (-6 - -5)2 + (4 - -4)2 )  =  sqrt( (-1)2 + (8)2 )  =  sqrt( 1 + 64 )  =  sqrt( 65)

 

The distance formula is just the Pythagorean Theorem applied to an x-y graph.

 

You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.

6 0
3 years ago
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