Equation of the line is -1/4x-5
From the question, we have
the given points (-8,-3) and (-12,-2) .
![y-y_1=(y_2-y_1)/(x_2-x_1 ) (x-x_1 )\\y+3=(-2+3)/(-12+8)(x+8)\\y+3=1/(-4)(x+8)\\y=-1/4 x-2-3\\f(x)=-1/4 x-5](https://tex.z-dn.net/?f=y-y_1%3D%28y_2-y_1%29%2F%28x_2-x_1%20%29%20%28x-x_1%20%29%5C%5Cy%2B3%3D%28-2%2B3%29%2F%28-12%2B8%29%28x%2B8%29%5C%5Cy%2B3%3D1%2F%28-4%29%28x%2B8%29%5C%5Cy%3D-1%2F4%20x-2-3%5C%5Cf%28x%29%3D-1%2F4%20x-5)
Slope:
A line's slope in mathematics is defined as the ratio of the change in the y coordinate to the change in the x coordinate.
Both the net change in the y-coordinate and the net change in the x-coordinate are denoted by y and x, respectively.
Consequently, the formula for the change in y-coordinate with respect to the change in x-coordinate is
m = y/x = y/x = change in y/change in x
where "m" represents a line's slope.
Slope, m = Change in y-coordinates/Change in x-coordinates
m = (y2 – y1)/(x2 – x1)
To learn more about slope visit: brainly.com/question/16180119
#SPJ9