Answer: the length is 11 cm.
The width is 7 cm.
Step-by-step explanation:
Let L represent the length of the rectangular plastic box.
Let W represent the width of the rectangular plastic box.
The area of the rectangular top of the box is 77 square cm. This means that
LW = 77- - - - - - - ;- - - -1
The plastic box has a length 4 cm longer than its width. This means that
L = W + 4
Substituting L = W + 4 into equation 1, it becomes
(W + 4)W = 77
W² + 4W = 77
W² + 4W - 77 = 0
W² + 11W - 7W - 77 = 0
W(W + 11) - 7(W + 11) = 0
W - 7 = 0 or W + 11 = 0
W = 7 or W = - 11
Since the width cannot be negative, then W = 7cm
L = 77/7 = 11 cm
(-4n^(2))* (5n^(7)):-20n to the power of 9
(2x)^(3)*(5x^(4 ))^(2): 200x to the power of 11
To find the midpoint, add x1 and x2 then divide by 2, then add y1 and y2 and divide by 2.
Midpoint = (2a +2b /2 , 0 + 2c /2)
Midpoint = a+b, c
Answer:
they are = to each other
Step-by-step explanation:
