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krek1111 [17]
1 year ago
14

9. The expression f(2) = 3 is equal to _______ A. Find the value of the function when x = 2 B. (3, 2) C. f(3) = 2 D. (2, 3)

Mathematics
1 answer:
egoroff_w [7]1 year ago
6 0

Step 1

Given; The expression f(2) = 3

Required to find what the expression is equal to

Step 2

From the function given when x=2, y=3

Therefore, the answer will be;

(2,3)

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F(x)=2x an$ g(x)=2x+3,what is the value of f(g(-8))
Fudgin [204]

First plug in g(x) into f(x)

F((g(x))=2(2x+3)

And now you plug in -8

F(g(-8))=2(-16+3)

F(g(-8))=2(-13)

F(g(-8))=-26

6 0
3 years ago
What is 6 8/15 as a percentage ( 6 and 8/15)
Black_prince [1.1K]

Answer:

6.53

Step-by-step explanation:

6*15+8=98\\98/15\\6.53

3 0
3 years ago
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Please help me!! Just help me solve
Kruka [31]
The solution for the system of equations are:
x =  \frac{7}{5} \\ y =  \frac{11}{5}
Attached is the graph of lines y=3x-2 and y=-2x+5.

4 0
3 years ago
What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE
maks197457 [2]

Given:

The equation of a line is:

2y+3x=10

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

2y+3x=10

For x=0,

2y+3(0)=10

2y+0=10

y=\dfrac{10}{2}

y=5

For x=2,

2y+3(2)=10

2y+6=10

2y=10-6

2y=4

Divide both sides by 2.

y=\dfrac{4}{2}

y=2

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

(x,y)\to (3x,3y)

Using this rule, we get

A(0,5)\to A'(3(0),3(5))

A(0,5)\to A'(0,15)

Similarly,

B(2,2)\to B'(3(2),3(2))

B(2,2)\to B'(6,6)

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-15=\dfrac{6-15}{6-0}(x-0)

y-15=\dfrac{-9}{6}(x)

y-15=\dfrac{-3}{2}x

Multiply both sides by 2.

2(y-15)=-3x

2y-30=-3x

2y+3x=30

Therefore, the equation of the line after the dilation is 2y+3x=30.

3 0
3 years ago
Write an expression in terms of x that represents the distance between (2,10) and (x,10) for x>2.
ehidna [41]

Answer:

Step-by-step explanation:

d=\sqrt{(x-2)^2+(10-10)^2} =\sqrt{(x-2)^2}=x-2

7 0
3 years ago
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