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1 year ago

5

Jenny's father works at the local grocery store. He just finished setting up a display of soup cans in the shape of a triangle.

There are 4 cans of soup in the top row. For each of the following rows, he added 2 cans of soup to each end, so there are 8 cans of soup in the second row, 12 in the third row, and so forth. How many cans of soup are in the 12th row?

1 answer:

Anit [1.1K]1 year ago

7 0

If i’m correct, the answer is simply 48!!

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inn [45]

Answer:

21

Step-by-step explanation:

Volume= (4/3)*pi*r^3

40007= (4/3)*pi*r^3

r=21m

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3 years ago

The midpoint of -7 and 8 on the number line is 1/2 true or false

Phoenix [80]

Answer:

True

Step-by-step explanation:

Yo find the midpoint between 2 points x1 and x2

midpoint = (x1+x2)/2

midpoint = (-7+8)/2

midpoint = 1/2

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3 years ago

I need this answer ?

FromTheMoon [43]

Are you sure you need help with that easy problem read it slowly then ask

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3 years ago

A student used the graph below to identify the minimum/maximum. The student said the graph had a maximum of 1. Explain the stude

11Alexandr11 [23.1K]

Answer: Answer is in the step.

Step-by-step explanation:

The student made a mistake by identifying the maximum point by the x coordinate value of the vertex. Minimum or maximum points are determine using the y coordinate value.The student can determine the difference between a maximum and minimum by identifying the y coordinate of the vertex.

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3 years ago

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

<em>The point </em> $(1\frac{1}{2},1)$ <em> won't be on the graph because the corresponding value of y for </em> $x = 1\frac{1}{2}$ <em> is </em> $y = 2\frac{1}{4}$ <em></em>

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

<em>The point </em> $(4,6)$ <em> would be on the graph because the corresponding value of y for </em> $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

<em>The point </em> $(18,12)$ <em> wouldn't be on the graph because the corresponding value of y for </em> $x = 18$ <em> is </em> $y = 12$ <em></em>

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

<em>The point </em> $(0,0)$ <em> would be on the graph because the corresponding value of y for </em> $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

<em>The point </em> $(2\frac{1}{2},3\frac{3}{4})$ <em> would be on the graph because the corresponding value of y for </em> $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago