Write an equation for a parabola opening upward, shifted 6 units right, and three units down
1 answer:
y = (x-6)²-3
1) Let's write a transformation described as it is, algebraically speaking.
• opening upward, (a >0)
,
• shifted 6 units right, (-6)
,
• and three units down -3
2) Starting from the parent function y=x², then we can write:
y = (x-6)²-3
Notice that the horizontal shift is within the parentheses with a swapped sign. And outside that -3 indicating the vertical shift.
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