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I am Lyosha [343]
1 year ago
7

Rewrite the equation of a circle given below in standard form x² + 2x + y² + 22y - 10 = 0

Mathematics
1 answer:
Verdich [7]1 year ago
7 0
x^2+2x+y^2+22y-10=0​\begin{gathered} x^2+2x+y^2+22y-10=0​ \\ (x^2+2x)+(y^2+22y)=10​ \\ (x^2+2x+2)+(y^2+22y+121)=10​+1+121 \\ (x^2+2x+1)+(y^2+22y+121)=132 \\ (x+1)^2+(y+11)^2=132 \end{gathered}

Answer:

(x+1)^2+(y+11)^2=132

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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30+5=5+30 with commutative property or 30+5=35 
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