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OverLord2011 [107]
3 years ago
6

Dave is helping his grandmother make trail mix. His grandmother asks him to add 1/5 cup of fruit for every 1/3 cup of nuts.

Mathematics
1 answer:
natita [175]3 years ago
8 0
The answer should be 3/5

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In deciding the best medium to tell a story, which step is first?(1 point)
zavuch27 [327]

Answer:

identifying the audience

Step-by-step explanation:

6 0
3 years ago
A mass club has 40 members the number of girls is five less than two times the number of boys how many members are boys how many
Lorico [155]

Answer:

15 boys and 25 girls

Step-by-step explanation:

The sum of boys (b) and girls (g) is given as 40:

g + b = 40

The number of girls is 2 times the number of boys minus 5:

2b - 5 = g

First formula can be rewritten as g = 40 - b

Then you can substitute this for g in the second, and you get:

2b-5 = 40-b

Which simplifies to:

2b + b = 40 + 5

3b = 45

b = 15

g = 40-15 = 25

15 boys, 25 girls.

6 0
3 years ago
45 is 9% of what? Would that be a/45 <br> 9/100
Natalija [7]
45 is 9% of 500!

<em>I hope this helps!</em>
7 0
3 years ago
Read 2 more answers
Ahmet is twice as old as his sister Betul, and the sum of their ages is 36. How old is Ahmet?
Dovator [93]
18??
two times as old.
36 divided but 2 is 18
4 0
3 years ago
What is the quadratic regression equation for the data set? ​ ​ ​ <br><br> PLEASEE HELP ME
Soloha48 [4]
You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b

Computing this, you'd find that

\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}

which means the first choice is correct.
8 0
3 years ago
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