Simplify and show your work please. 3x+6y+x+3(2x+3y

Mathematics

2 answers:

kumpel [21]3 years ago

7 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

Sliva [168]3 years ago

5 0

<h3>Answer:hey there...8x^2+24xy+6x+18y^2 is the answer</h3>

Step-by-step explanation:

<h3>3x+6y+x+3(2x+3y)</h3><h3>=(2x *3x)+(2x*6y)+(2x*x)+(2x*3)+(3y *3x)+(3y *6y)+(3y*x)+(3y *3)</h3><h3>=6x^2+12xy+2x^2+6x+9xy+18y^2+3yx+9y</h3><h3>=8x^2+24 xy+6x+18y^2</h3><h3>hope this helped uuu</h3>

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If m < 0 and b > 0, the graph of y = mx + b does not pass through which quadrant?

stiks02 [169]

Answer:

Quadrant III

Step-by-step explanation:

The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.

The graphs shown are of the functions:

$y=-2x+1$