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Lerok [7]
1 year ago
5

Determine the volume of the shaded area.

Mathematics
1 answer:
vovikov84 [41]1 year ago
4 0

The shaded area in the image is 86.1 square inches.

<h3>How to get the shaded area?</h3>

Remember that for a circle of diameter D, the area is given by:

A = pi*(D/2)²

Where pi = 3.14, and here we have half-circles, so we need to add a factor 0.5

The area of the shaded figure, the area of the shaded figure will be the area of the half circle with diameter of 17in minus the area of the half circle with a diameter of 8.5 in, so the area is:

area = 0.5*3.14*(17in/2)² - 0.5*3.14*(8.5in/2)² = 86.1 in²

Learn more about area:

brainly.com/question/24487155

#SPJ1

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Brian has three basketball cards and five baseball cards what fraction of Brian‘s cards are baseball cards
Anon25 [30]

Answer:

5 / (3 + 5) = 5/8 are baseball cards

4 0
3 years ago
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Find the center and radius for the circle, given the equation: x^2-14x+y^2+8=16
Strike441 [17]
You can do this by completing the square

x^2 - 14x + y^2 + 8  = 16

(x - 7)^2 - 49 + (y + 4)^2 - 16  = 16

(x - 7)^2 + (y + 4)^2 =   16 + 16 + 49  =  81


so the center is at (7 , -4) and radius = sqrt81 = 9
5 0
3 years ago
Leiff goes online to buy a new video game. He finds a site that currently has a promotion of 15% off on all orders over $50. Lei
Hatshy [7]

Answer:

$119.32

Step-by-step explanation:

Leiff decides to buy his video game, with a price tag of $128, at this site

he will get the 15% discount when he checks out.

100-15= 85%

Discounted price=85% of 128 is 0.85 \cdot 128=108.8

Leiff pays 5.3% sales tax on the discounted price

5.3% is 0.053

sales tax amount=0.053 times 108.8=5.7664

So we add the sales tax amount and shipping fee

108.8+5.7664+4.75=119.32

So $119.32 is the total amount

6 0
3 years ago
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PLS 40 points
Pavlova-9 [17]
<h2>2x+y=2</h2>

Step-by-step explanation:

Let p1 be the point (-1,4)

Let p2 be the point (3,-4)

The equation of the line passing through two points p1=(x_{1},y_{1})

and p2=(x_{2},y_{2}) is \frac{y-y_{1}}{x-x_{1}} =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

substituting p1,p2 in the above equation yields

\frac{y-4}{x-(-1)}=\frac{-4-4}{3-(-1)}

which when simplified gives \frac{y-4}{x+1}=\frac{-8}{4}

which when further simplified gives 2x+y=2

5 0
3 years ago
Find the indicated limit, if it exists.
kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Limit Property [Addition/Subtraction]:                                                                   \displaystyle \lim_{x \to c} [f(x) \pm g(x)] =  \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}

<u>Step 2: Find Right-Side Limit</u>

  1. Substitute in function [Limit]:                                                                         \displaystyle  \lim_{x \to 5^+} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 5^+} 5 - x = 5 - 5 = 0

<u>Step 3: Find Left-Side Limit</u>

  1. Substitute in function [Limit]:                                                                         \displaystyle  \lim_{x \to 5^-} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

∴ Since  \displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)  , then  \displaystyle \lim_{x \to 5} f(x) = DNE

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Limits

5 0
2 years ago
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