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Alecsey [184]
3 years ago
13

Im starting to have problems with this

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0

Answer:

x= 4.24

Step-by-step explanation:

AfilCa [17]3 years ago
4 0
X=4.24 is most likely the right answer like the other answer you have gotten
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If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .​
Tems11 [23]

Divide through everything by <em>b</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}

Since <em>a/b</em> < <em>c/d</em>, it follows that

\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}

Multiply through everything on the right side by <em>b/d</em> to get

\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}

and <em>a/b</em> < <em>c/d</em> tells us that

\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}

Then

\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

5 0
3 years ago
Which of the following is either a median or an altitude?
Blizzard [7]

Answer:

PR is an altitude

QT is a median.

Step-by-step explanation:

The altitude is the perpendicular height and the median is a line from 1 vertex to the middle of the opposite side.

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Oxana [17]

Answer: you did not explain it well if you did i would know it but i think i=7 w=18 h=25

Step-by-step explanation:

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Answer:

-11 im pretty sure

Step-by-step explanation:

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3 years ago
How many cubic inches are in 1 cubic foot
AleksandrR [38]

\text{There are}\\ 12^3=1728 \\\text{cubic inches in a cubic foot.}

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