On the unit circle, an angle terminates at the coordinate (x,y). What is the relationship between the x and y components of the
coordinate and the trig functions sin and cos?How can we use those relationships to predict the sign (+/-) for these trig functions when an angle terminates within a given quadrant?
1 answer:
The unit circle is represented below:
As can be observed in the figure above, for an angle (t), the relation between the trigonometric functions and x and y components is:
x = cos(t)
y = sen(t)
x is positive in the first and in the fourth quadrant. Thus, cos (t) will be positive for angles in the first and fourth quadrant.
y is positive in the first and in the second quadrant. Thus, sin (t) will be positive for angles in the first and second quadrant.
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The length of the insect in the final image is .
Further explanation:
In the question it is given that if an object is viewed under a microscope then the object appears times large than its original size.
It is given that the length of a insect is centimeter.
This question is based on the concept of multiplication of decimals.
Consider the length of the insect as .
Since, the length of insect is centimeter so, trhe value of
is
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As per the question the size of the final image is times large as the original size so, the size of final image is calculated as follows:
Substitute for
in the above equation.
From the above calculation it is concluded that the length of the insect in the final image is .
Therefore, the length of the insect in the final image is .
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Answer details:
Grade: Junior school
Subject: Mathematics
Chapter: Simplification
Keywords: Microscope, insect, cenimeter, magnifies, 0.095cm, 100 times, eyepiece, viewed, 9.5cm, simplification, multiplication, decimals, final image.
Answer:
The change in temperature per minute for the sample, dT/dt is 71. °C/min
Step-by-step explanation:
The given parameters of the question are;
The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)
The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min
Given that both dQ/dT and dQ/dt are known, we have;
Therefore, we get;
For the sample, we have the change in temperature per minute, dT/dt, presented as follows;