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Leto [7]
2 years ago
5

Question 9 of 25

Mathematics
2 answers:
tresset_1 [31]2 years ago
8 0

Answer:

One approach to this problem is to obtain the graph for the given equation.

We need to find every intersection those functions have with the axis 'x' and 'y'

starting with g(x)

g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis

g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis

Lets do the same for f(x)

g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis

We dont need to find any other, since always y=x

By plotting we have the attached picture

Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.

Step-by-step explanation:

KengaRu [80]2 years ago
8 0

Answer:

If f(x) = x  and  g(x) = x - 3

then g(x) = f(x) - 3

So g(x) is a translation of f(x) by 3 units down.

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What is the equation of the line in the slope intercept form
Grace [21]

Answer:

<em>Equation of line; y = - 6x</em>

Step-by-step explanation:

As we can see from this graph, point ( 0, 0 ) lying on this graph intersects the y - axis such that it forms a y - intercept of 0;

At the same time we can note that the change in y / change in x, in other words the slope, differs by a rise of 6 / run of - 1, 6 / - 1 being a slope of - 6;

If this equation is in slope - intercept form ⇒

y = a * x + b, where a ⇒ slope, and b ⇒ y - intercept,

<em>Equation of line; y = - 6x</em>

7 0
3 years ago
Read 2 more answers
Part A picture above
-BARSIC- [3]

Answer:

<em>Part A </em>C = (10,5)<em>  Part B </em>C. D'(0,10)

Step-by-step explanation:

<em>Part A</em>

Since c is at the point (2,1) in relation to the origin, we can multiply those distances by our scale factor of 5

(2,1) * 5 = (10,5)

The new point C is going to be (10,5)

<em>Part B</em>

If you dilate with a factor of 5 -- relative to the origin -- you have to multiply the distance from <em>the origin</em> by 5.

In this case, point D is already on the y axis, so it's x value wouldn't be affected. Point D is currently 2 units away from (0,0), so we can multiply 2*5 to get 10 -- our ending point is (0,10)

8 0
3 years ago
1(x-2)= -5.5 solving for x. What's the answer
Lapatulllka [165]

Answer:

x = -3.5

Step-by-step explanation:

1(x-2) = -5.5

x-2 = -5.5

 +2    +2

x = -3.5

3 0
3 years ago
What do you notice about the table inputs for the graph of √x?
Airida [17]

Answer:

See below

Step-by-step explanation:

When we talk about the function f(x)=\sqrt{x}, the domain and codomain are generally defaulted to be subsets of the Real set. Once $f:[0,\infty)\to [0,\infty)$ and  $f\subseteq [0,\infty)\times [0,\infty)$ such that $(x,y_1)\in f\wedge(x,y_2)\in f \Rightarrow y_1=y_2$  for $f(x)=\sqrt x$. Therefore,

\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]

\[x \mapsto \sqrt{x}\]

But this table just shows the perfect square solutions.

4 0
2 years ago
Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.
Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

 outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

 and join the outside point with center of the circle, we

 formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

  angle between them in one triangle equal to the

  corresponding sides and angles in the second triangle,

  then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

8 0
3 years ago
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