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fenix001 [56]
1 year ago
11

U

Engineering
2 answers:
iragen [17]1 year ago
4 0

Answer:  the answer is B

Explanation:

Sergio039 [100]1 year ago
3 0

Answer:

your answer is B

Explanation:

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Lawn maintenance is an alternative energy source<br> -true<br> -false
Reika [66]

Answer:

false

Explanation:

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3 years ago
Air at 1 atm enters a thin-walled ( 5-mm diameter) long tube ( 2 m) at an inlet temperature of 100°C. A constant heat flux is ap
alexdok [17]

Answer:

heat rate   = 7.38 W

Explanation:

Given Data:

Pressure = 1atm

diameter (D) = 5mm = 0.005m

length = 2

mass flow rate (m) = 140*10^-6 kg/s

Exit temperature = 160°C,

At 400K,

Dynamic viscosity (μ) = 22.87 *10^-6

Prandtl number (pr) = 0.688

Thermal conductivity (k) = 33.65 *10^-3 W/m-k

Specific heat (Cp) = 1.013kj/kg.K

Step 1: Calculating Reynolds number using the formula;

Re = 4m/πDμ

     = (4*140*10^-6)/(π* 0.005*22.87 *10^-6)

     = 5.6*10^-4/3.59*10^-7

     = 1559.

Step 2: Calculating the thermal entry length using the formula

Le = 0.05*Re*Pr*D

Substituting, we have

Le = 0.05 * 1559 * 0.688 *0.005

Le = 0.268

Step 3: Calculate the heat transfer coefficient  using the formula;

Nu = hD/k

h = Nu*k/D

Since Le is less than given length, Nusselt number (Nu) for fully developed flow and uniform surface heat flux is 4.36.

h = 4.36 * 33.65 *10^-3/0.005

h = 0.1467/0.005

h = 29.34 W/m²-k

Step 4: Calculating the surface area using the formula;

A = πDl

   =π * 0.005 * 2

    =0.0314 m²

Step 5: Calculating the temperature Tm

For energy balance,

Qc = Qh

Therefore,

H*A(Te-Tm) = MCp(Tm - Ti)

29.34* 0.0314(160-Tm) =  140 × 10-6* 1.013*10^3 (Tm-100)

0.921(160-Tm) = 0.14182(Tm-100)

     147.36 -0.921Tm = 0.14182Tm - 14.182

1.06282Tm = 161.542

Tm = 161.542/1.06282

Tm = 151.99 K

Step 6: Calculate the rate of heat transferred using the formula

Q = H*A(Te-Tm)

   = 29.34* 0.0314(160-151.99)

  = 7.38 W

the Prandtl number using the formula

5 0
3 years ago
Three methods by which the value of the unknown resistance can be determined​
Contact [7]

Answer:

The Meter bridge is the modification of Wheatstone's network used to determine the value of unknown resistance. The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.

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What is the advantage of having the engine in the front of the car?
Ugo [173]

Answer:

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Explanation:

hehehehe DONTTTT report my answer

8 0
3 years ago
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The output S/N at thereceiver must be greater than 40 dB. The audio signal has zero mean, maximum amplitude of 1, power of ½ Wan
abruzzese [7]

Given that,

The output signal at the receiver must be greater than 40 dB.

Maximum amplitude = 1

Bandwidth = 15 kHz

The power spectral density of white noise is

\dfrac{N}{2}=10^{-10}\ W/Hz

Power loss in channel= 50 dB

Suppose, Using DSB modulation

We need to calculate the power required

Using formula of power

P_{L}_{dB}=10\log(P_{L})

Put the value into the formula

50=10\log(P_{L})

P_{L}=10^{5}\ W

For DSB modulation,

Figure of merit = 1

We need to calculate the input signal

Using formula of FOM

FOM=\dfrac{\dfrac{S_{o}}{N_{o}}}{\dfrac{S_{i}}{N_{i}}}

1=\dfrac{\dfrac{S_{o}}{N_{o}}}{\dfrac{S_{i}}{N_{i}}}

\dfrac{S_{i}}{N_{i}W}=\dfrac{S_{o}}{N_{o}}

Put the value into the formula

\dfrac{S_{i}}{2\times10^{-10}\times15\times10^{3}}

\dfrac{S_{i}}{30\times10^{-7}}

S_{i}

S_{i}=30\times10^{-3}

We need to calculate the transmit power

Using formula of power transmit

S_{i}=\dfrac{P_{t}}{P_{L}}

P_{t}=S_{i}\times P_{L}

Put the value into the formula

P_{t}=30\times10^{-3}\times10^{5}

P_{t}=3\ kW

We need to calculate the needed bandwidth

Using formula of bandwidth for DSB modulation

bandwidth=2W

Put the value into the formula

bandwidth =2\times15

bandwidth = 30\ kHz

Hence, The transmit power is 3 kW.

The needed bandwidth is 30 kHz.

3 0
3 years ago
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