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Ira Lisetskai [31]
3 years ago
13

Describe with an example how corroded structures can lead to environment pollution? ​

Engineering
1 answer:
Reil [10]3 years ago
8 0
An example to describe how it can lead to environment pollution is littering into the oceans , that’s one example how it can help lead to environment pollution , Hope this helps !
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Compare the output of full-wave rectifier with and without filter
lara31 [8.8K]

Answer:

Full wave rectification flips the negative half cycle of the sine wave to positive so the result is two positive half cycles.

Explanation:

hope it helps a lil

4 0
3 years ago
A car engine with a thermal efficiency of 33% drives the air-conditioner unit (a refrigerator) besides powering the car and othe
fgiga [73]

Answer:

The rate of fuel required to drive the air conditioner Q_h = 6.061 kW

The flow rate of the cold air is  \r m = 0.30765 kg/s

Explanation:

From this question we are told that

    The efficiency is \eta = 33% = 0.33

   Temperature for the hot day is  T_h = 35^oC = 308 K \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (35+273)

        Temperature after cooling is  T_c = 5^oC = 278K

      The input power is  P_{in} = 2kW

The rate of fuel required to drive the air conditioner can be mathematically represented as

              Q_h = \frac{P_{in}}{\eta}

                    = \frac{2}{0.33} = 6.061 kW

From the question the air condition is assumed to be half as a Carnot refrigeration unit

 This can be Mathematically interpreted in terms of COP(coefficient of performance) as

             \beta_{air} = 0.5 \beta

where \beta  denotes COP and is mathematically represented as

                     \beta = \frac{Q_c}{P_{in}}

= >              Q_c = \beta P_{in}

Where Q_c is the rate of flue being burned for cold air to flow

Now if  the COP of a Carnot refrigerator is having this value

                \beta_{Carnot } = \frac{T_c}{T_h - T_c}

                            = \frac{278}{308-278}

                            \beta_{Carnot} = 9.267\\

Then

     \beta_{air} = 0.5 * 9.2667

            = 4.6333

Now substituting the value of \beta to solve for Q_c

                             Q_c = \beta P_{in}

                                  = 4.6333 *2

                                  9.2667kW

The equation for the rate of fuel being burned for the cold air to flow

                       Q_c = \r mc_p \Delta T

Making the flow rate of the cold air

                       \r m = \frac{Q_c}{c_p \Delta T}

                            = \frac{9.2667}{1.004}* (308 - 278)

                            = 0.30765 kg/s

                         

                             

4 0
3 years ago
4.
Stella [2.4K]
A gas cylinders be cleaning chemical see wedding rods de leathers must be stored in and approve steel cabinet
3 0
3 years ago
que sabemos de la revolución industrial y como ese proceso impulso el uso de los controles eléctricos en las industrias
Alex Ar [27]

Answer:

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Explanation:

8 0
3 years ago
The charpy test determines?
Finger [1]

Answer:

The charpy test is used to determine amount of energy a material absorbs at fracture.

Explanation:

Charpy Impact test was developed by a French scientist to determine the amount of energy a material absorbs at fracture hence giving the toughness of the material. It is widely used in industrial applications since it is easy to perform and does not requires sophisticated equipment to perform.

The test is performed when a swinging pendulum of known weight  is dropped from a known height and is made to strike the metal specimen which is notched.The notch in the sample affects the results of the test hence the notch should be standardized while performing the test. The qualitative results obtained can also be used to compare ductility of different materials.

4 0
4 years ago
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