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Oksana_A [137]
3 years ago
12

Problem the pressure at a given point is 50 mmhg absolute

Engineering
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

6.65 kPa.

- 73.3 kPa.

Explanation:

Without much ado let's jump right into the solution to the problem given. It is given that the pressure = 50 mmHg and the solution to this question is to write out the value of the pressure in kpa and kPa gauge.

P(a) = 0.05m × 133 kN/m³ = 6.65 kPa.

The P(gauge) =( [ 0.05 × 13.6 × 9810] ÷ 1000 ) - 80 = - 73.3 kPa.

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The "Crawler" developed to transport the Saturn V launch vehicle from the assembly building to the launch pad is the largest lan
Illusion [34]

Answer:

a) 152000 slugs

b) 2220000 kg or 2220 metric tons

Explanation:

A body with a weight of 4.9*10^6 lbf has a mass of

4.9*10^6 lbm * 1 lbf/lbm = 4.9*10^6 lbm

This mass value can then be converted to other mass values.

1 slug is 32.17 lbm

Therefore:

4.9*10^6 lbm * 1 slug / (32.17 lbm) = 152000 slugs

1 lb is 0.453 kg

Therefore:

4.9*10^6 lbm / (1/0.453) * kg/lbm = 2220000 kg

5 0
3 years ago
The development team recently moved a new application into production for the accounting department. After this occurred, the Ch
Novay_Z [31]

Answer: (A) Security regression testing

Explanation:

  The security regression testing is used to prevent the re-occurring process. The regression testing is the type of the testing that intends to affirm that a program or code or application changes has not influenced existing highlights and it keeps up the agenda.

The agenda ought to be similarly identified with necessity that was concluded. By checking this both then relapse testing occurs and this won't reoccurred from next time.

The regression testing improvements groups must ensure that changes, updates and new discharges don't presents imperfections and vulnerabilities that could be misused by the people.

4 0
4 years ago
Consider a single bacterial cell as a discrete particle with a diameter of 1x10-6m and a specific gravity of 1.01. Assuming lami
Alinara [238K]

Answer:

Sedimentation is not a good method.

Explanation:

We need to apply Stoke laws and assume that is valid here.

So,

V_s= 418(G-1)d^2(\frac{3T+70}{100})

Replacing the values,

V_s= (418)(1.01-1)(10^-3)^3*(\frac{3*20+70}{100})\\V_s=5.434*10^-6mm/s

Here then we calculate the time,

t_{req}=\frac{x}{v}

Where x= Distance, v= velocity

t_{req}=\frac{1foot}{5.434*10^{-6}} = \frac{304.8}{5.434*10^{-6}}\\t_{req}=649.2days

To calculate the surface required we need first to calculate the volume through the volume,

So,

Q=4MGD=4*10^6*0.135 (ft^3/day)

Then,

V_{req} = Q*t\\V_{req}=4*10^6*0.134*649.2\\V_{req}=34.79*10^7ft^3

Here we can calculate the surface

S_{req}= \frac{Volume}{Distance}=\frac{34.79*10^7}{1}\\S_{req}=7987.8 Acres

<em>So, the requeriment of Area of tank and settlement time is huge, it's not a practical method.</em>

6 0
3 years ago
(a) Aluminum foil used for storing food weighs about 0.3 grams per square inch. How many atoms of aluminum are contained in one
atroni [7]

Answer:

note:

solution is attached due to error in mathematical equation. please find the attachment

3 0
3 years ago
The 2-kg package leaves the conveyor belt at with a speed of vA = 1 m/s and slides down the smooth ramp. Determine the required
Kisachek [45]

Answer:

Incomplete question: Find the normal reaction the curved portion of the ramp exerts on the package at B if pB = 2 m, the height is 4 m

Answer: The required speed is 8.9107 m/s

The normal reaction is 99.0006 N

Explanation:

Given data:

m = 2 kg

vA = speed = 1 m/s

h = 4 m

g = gravity = 9.8 m/s²

Questions: Determine the required speed of the conveyor, vc = ?

Find the normal reaction, Nc = ?

The required speed applying the conservation of energy:

\frac{1}{2} mv_{A}^{2}  +mgh=\frac{1}{2} mv_{c} ^{2}

Solving for vc:

v_{c} =\sqrt{v_{A}^{2}+2gh  } =\sqrt{1^{2}+(2*9.8*4) } =8.9107m/s

The normal reaction applying the equilibrium of forces:

N_{c} -mg=m(\frac{v_{c}^{2}  }{p_{B} } )

N_{c} =2*(\frac{8.9107^{2} }{2} )+(2*9.8)=99.0006N

3 0
3 years ago
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