Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
The total amount of the resulting mixture can be calculated by adding up the volume of the given substances assuming that volume addition is applicable given the properties of the fluids used.
That is,
T = 6 quarts + 10 quarts = 16 quarts
The total volume of the resulting mixture is 16.
Then, we do the component (antifreeze) balance by adding up the resulting antifreeze from the substances to the total. We let x be the percentage of antifreeze in the final mixture.
6(0.52) + 10(0.32) = 16(x)
The value of x from the equation is 0.395.
Therefore, the answer to this item is 39.5%.
<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

Compare the terms.

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)

Factor (-2)^3 out.

(-2) • (-2) = 4 | Negative × Negative = Positive.

4 • (-2) = -8 | Negative Multiply Positive = Negative.

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.
Hence,

The answer is - 1 / 8
Linear, because the graph of the line is just a straight line without any curves, and the power of x is 1. If x was raised to the second, third, fourth, etc. power, it would be a nonlinear equation.