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Paha777 [63]
3 years ago
8

If y varies directly as x, and y is 400 when x is randy is r when x is 4, what is the numeric constant of variation in this rela

tion?
10
40
100
Mathematics
1 answer:
juin [17]3 years ago
5 0

The numeric constant of variation is 100

Step-by-step explanation:

Direct proportion means that increase in one variable cause increase in other variable

Here,

It is given that

y varies directly as x

y∝x

when the proportionality symbol is removed a proportionality constant is introduced

y = kx

Given that

y = 100 when x = 4

Putting the values

400 = k * 4\\k = \frac{400}{4}\\k = 100

The numeric constant of variation is 100

Keywords: Proportion variation

Learn more about direct proportion at:

  • brainly.com/question/1234767
  • brainly.com/question/1232765

#LearnwithBrainly

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The Magazine Mass Marketing Company has received 1515 entries in its latest sweepstakes. They know that the probability of recei
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Answer:

P(x < 5)=P(X=0)+P(X=1)+P(X=2)+P(x=3)+P(X=4)

P(X=0)=(15C0)(0.5)^0 (1-0.5)^{15-0}=0.0000305

P(X=1)=(15C1)(0.5)^1 (1-0.5)^{15-1}=0.000458

P(X=2)=(15C2)(0.5)^2 (1-0.5)^{15-2}=0.0032

P(X=3)=(15C3)(0.5)^3 (1-0.5)^{15-3}=0.0139

P(X=4)=(15C4)(0.5)^4 (1-0.5)^{15-4}=0.0417

And adding we got:

P(x < 5)=0.0592

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=15, p=0.5)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(x < 5)=P(X=0)+P(X=1)+P(X=2)+P(x=3)+P(X=4)

P(X=0)=(15C0)(0.5)^0 (1-0.5)^{15-0}=0.0000305

P(X=1)=(15C1)(0.5)^1 (1-0.5)^{15-1}=0.000458

P(X=2)=(15C2)(0.5)^2 (1-0.5)^{15-2}=0.0032

P(X=3)=(15C3)(0.5)^3 (1-0.5)^{15-3}=0.0139

P(X=4)=(15C4)(0.5)^4 (1-0.5)^{15-4}=0.0417

And adding we got:

P(x < 5)=0.0592

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Answer:

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Answer:

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