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ASHA 777 [7]
1 year ago
14

HOW Does 1/6, -3, square root 7, -6/5 or 45 come first when the numbers are listed from lest to greatest. explain PLEASE EXPLAIN

ME!!!!!!!!!!!!!!!! :C(
Mathematics
2 answers:
max2010maxim [7]1 year ago
8 0

Answer:

-3 < -6/5 < 1/6 < √7 < 45

Step-by-step explanation:

Now the values will be,

→ 1/6 = 0.17

→ -3 = -3

→ √7 = 2.65

→ -6/5 = -1.2

→ 45 = 45

Let's arrange in ascending order,

→ -3, -1.2, 0.17, 2.65, 45

→ -3, -6/5, 1/6, √7, 45

Hence, number -3 comes first.

svetlana [45]1 year ago
4 0

Answer:

  • - 3 comes first and the order is - 3, - 6/5, 1/6, √7, 45

==========================

<h3>Given numbers</h3>

  • 1/6, - 3, √7, - 6/5, 45.

<h3>Put these numbers in the ascending order</h3>

First, compare the negative numbers as they are smaller than positives since negatives are to the left from zero on the number line and positives are to the right.

  • - 3 vs - 6/5
  • - 3*5/ 5 vs - 6/5
  • - 15/5 vs - 6/5

Since - 15 is smaller than - 6, the least number is - 3:

  • - 15/5 < - 6/5 ⇒  - 3 < - 6/5

Now compare the positives.

  • 1/6 is smaller than 1 as it is a fraction.
  • √4 < √7 < √9 ⇒ 2 < √7 < 3, so √7 is between 2 and 3, hence greater than 1, therefore 1/6 < √7.
  • And the greatest number is 45 as it is greater than 3.

Therefore:

  • 1/6 < √7 < 45

The complete order is:

  • - 3, - 6/5, 1/6, √7, 45
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