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3 years ago

Given the relation R = {(-2, 3), (a, 4), (1,9), (0,7)}.

Mathematics

1 answer:

aniked [119]3 years ago

4 0

Answer:

The answer would be 4

Step-by-step explanation:

you can’t have repeating numbers in a function.

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Luis used compensation to find 6,572-239 compensation methods u

saveliy_v [14]

Here is the solution...

Compensation

The compensation is nothing but the process of reforming the given expression to find the answer mentally.

Here we need to rewrite the given expression in order find the answer mentally.

Step 1:

Here we can add 8 with 6572, so we get 6580.

Step 2:

Add 8 from 239, so we get 247.

Step 3:

We can rewrite 247 as 240 + 7

Step 4:

Now we can subtract 240 from 6580, so we get 6340.

We can calculate this mentally.

Step 5:

Finally, we can subtract 7 from 6340 mentally, So we get

6333.

Mathematically, the above expression written as

6572- 239

= 6572 + 8 - (239 + 8)

= 6580 - 247

= 6580 - (240 + 7)

= 6580 -240 - 7

= 6340 - 7

= 6333

3 0

3 years ago

I will award brainliest!!!

stepan [7]

Answer: The measure of non-reflex ∠DOB is 108° and the measure of reflex ∠DOB is 252°.

Explanation:

It is given that the reflex angle ∠DOB has measure of 3.5y while the measure of ∠AOD is y.

From the given figure we can say that angle AOC and COB are supplementary angles and their sum is 180 because they are lies on a straight line.

$\angle DOB=\angle AOD+\angle AOC+\angle COB$

$3.5y=y+180$

$3.5y-y=180$

$2.5y=180$

$y=72$

Therefore the value of y is 72.

$\angle DOB=3.5y$

$\angle DOB=3.5\times 72$

$\angle DOB=252$

Therefore the reflex and is 252 degree.

The measure of non-reflex ∠DOB is,

$\angle DOB=360-252=108^{\circ}$

Therefore, the measure of non-reflex ∠DOB is 108° and the measure of reflex ∠DOB is 252°.

6 0

3 years ago

Solve for the roots in simplest form by completing the square 6x^2+120x+2070=0

Kitty [74]

Answer:

Step-by-step explanation:

First, we can divide out the common factor, 6

$6x^2 + 120x + 2070 = 0\\x^2 + 20x + 345 = 0\\$

Now we complete the square

$(x^2 + 20x + (\frac{20}{2})^2) + 345 - (\frac{20}{2})^2\\(x^2 + 20x + 100) + 345 - 100\\(x+10)^2 + 245\\$

$(x+10)^2 = -245\\x + 10 = \sqrt{-245}\\x = i\sqrt{245} - 10\\x = -10 \pm i\sqrt{245}$

8 0

3 years ago

The lines 2x=ky+2 and (k+1)x=6y-3 have same gradient. Find possible values of k

faust18 [17]

Answer:

k = 3 or k = -4

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

$2x=ky+2\to\ eq1\\(k+1)x=6y-3\to\ eq2\\$Change to this form: $y=mx+c\\ky=2x-2\\y=\frac{2x-2}{k}\\$gradient of eq1: $\frac{2}{k}\\6y=(k+1)x+3\\y=\frac{(k+1)x+3}{6}\\y=\frac{k+1}{6} x+\frac{3}{6}\\y= \frac{k+1}{6} x+\frac{1}{2}\\$gradient of eq1: $\frac{k+1}{6}\\$Since gradient, m, is the same for both lines,$\\\frac{2}{k}=\frac{k+1}{6}\\12=k^{2}+k\\k^{2}+k-12=0\\(k-3)(k+4)=0\\k=3 $ or $ k=-4$

6 0

3 years ago

Hi guys Im new here I'm indonesian :)))))))))))

Darina [25.2K]

welll hello

Step-by-step explanation:

i am honsetly

just trying

to get pionts

6 0

3 years ago

Read 2 more answers