The point-slope form of a line is:
y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line
First we need to find the slope, which is (y2-y1)/(x2-x1)
m=(4--1)/(8-2)
m=5/6 and we can use either point, I'll use (8,4)
y-4=(5/6)(x-8)
That is your equation in point-slope form.
Now the standard equation of a line is ax+by=c
y-4=(5/6)(x-8) we can perform the indicated multiplication on the right side
y-4=(5x-40)/6 multiply both sides by 6
6y-24=5x-40 add 24 to both sides
6y=5x-16 subtract 5x from both sides
-5x+6y=-16 and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1
5x-6y=16
Start: 8 a. m.
Finish: 1 : 30 p.m. = 13 hours 30 minutes
13 h 30 min - 8 h = 5 h 30 min
She should record 5 hours and 30 minutes on her time card for the day.
F(x) = (2x-1)(x+2)/ (x+2)
f(x) = 2x-1
f(-2) = 2(-2)-1
f(-2) = -5
Answer:
(-37+43)-44=x
Step-by-step explanation:
i put the parentheses only because of PEMDAS. it's a pretty straightfoward question. To put it in an expression however, I'm not sure. Best of luck!