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Bezzdna [24]
1 year ago
15

Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three op

tions. The value of f(–10) = 82 The graph of the function is a parabola. The graph of the function opens down. The graph contains the point (20, –8). The graph contains the point (0, 0).
Mathematics
1 answer:
lutik1710 [3]1 year ago
5 0

The statement that is true about the quadratic function is (b) the graph of the function is a parabola.

<h3>How to determine the true statements?</h3>

The quadratic function is given as

f(x) = x2 – 5x + 12

Rewrite as

f(x) = x² – 5x + 12

All quadratic functions are parabola

This means that option (b) is true

Set x = -10 to calculate f(-10)

So, we have

f(-10) = (-10)² – 5(-10) + 12

Evaluate

f(-10) = 162

This means that option (a) is false

Set x = 20 to calculate f(20)

So, we have

f(20) = (20)² – 5(20) + 12

Evaluate

f(20) = 312

This means that option (d) is false

Set x = 0 to calculate f(0)

So, we have

f(0) = (0)² – 5(2) + 12

Evaluate

f(0) = 12

This means that option (e) is false

The leading coefficient in f(x) = x² – 5x + 12 is positive

Graphs with positive leading coefficient opens up

This means that option (c) is false

Hence, the true statement about the quadratic function is (b)

Read more about quadratic functions at

brainly.com/question/1214333

#SPJ1

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Suppose a student started with 139.0 mg of trans-cinnamic acid, 463 mg of pyridinium tribromide, and 2.45 mL of glacial acetic a
Sliva [168]

Answer:

0.2889 g  brominated product

64.6 %

Step-by-step explanation:

This is a bromination chemical reaction of an alkene  and we are asked to calculate the theoretical and percent yield. Thus to solve it we have to perform a calculation based on the balanced chemical reaction.

The pyridinium tribromide is used as a generator of molecular bromine in situ, and bromine will add to the double bond in trans-cinnamic acid so we know the reaction occur in a one to one mole fashion.

trans-cinnamic acid + pyridinium  tribromide ⇒ 2,3-dibromo-3-                          

                                                                             phenylpropanoic acid

Molar weight  trans-cinnamic acid  =  148.16 g/mol

mass trans-cinnamic acid  = 139.0 mg x  1g/1000 mg = 0.139 g

# mol trans-cinnamic acid =  0.139 g / 148 g/mol = 9.38 x 10⁻⁴ mol

Since our reaction is 1 mol trans-cinnamic acid  produces 1 mol 2,3-dibromo-3-phenylpropanoic acid, it follows that the theoretical yield is:

1 mol 2,3-dibromo-3-phenylpropanoic acid /  trans-cinnamic acid x 9.38 x 10⁻⁴ mol trans-cinnamic acid  

=  9.38 x 10⁻⁴ mol  2,3-dibromo-3-phenylpropanoic acid

In grams the the theoretical yield is:

molar mass  2,3-dibromo-3-phenylpropanoic acid = 307.97 g/mol

The theoretical mass  2,3-dibromo-3-phenylpropanoic acid:

=   9.38 x 10⁻⁴ mol  2,3-dibromo-3-phenylpropanoic acid x 307.97 g/mol

=   0.2889 g

% yield = mass experimental/mass theoretical

= 0.1866 g /  0.2889 g x 100 = 64.6 %

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