Answer:
the slope of both lines are the same.
Step-by-step explanation:
Given the following segment of the Quadrilateral EFGH on a coordinate Segment FG is on the line 3x − y = −2,
segment EH is on the 3x − y = −6.
To determine their relationship, we can find the slope of the lines
For line FG: 3x - y = -2
Rewrite in standard form y = mx+c
-y = -3x - 2
Multiply through by-1
y = 3x + 2
Compare
mx = 3x
m = 3
The slope of the line segment FG is 3
For line EH: 3x - y = -6
Rewrite in standard form y = mx+c
-y = -3x - 6
Multiply through by-1
y = 3x + 6
Compare
mx = 3x
m = 3
The slope of the line segment EH is 3
Hence the statement that proves their relationship is that the slope of both lines are the same.
Answer:
y - 1 = -4(x - 4)
Step-by-step explanation:
The point-slope form looks like y-k = m(x-h), where (h,k) is a point on the line and m is the slope.
Here, y - 1 = -4(x - 4). This is in point-slope form.
28................................................
A slope intercept form: y = mx + b where m = slope and b = y -intercept
A slope of 3/2 is given
So y = 3/2 x + b
To find b:
b = y - mx
A line passes through the point (4, -6)
b = -6 - (3/2)(4)
b = -6 - 6
b = - 12
Answer
Equation in slope intercept form: y = 3/2 x - 12
