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tia_tia [17]
3 years ago
12

"write the expression in the exponential form:"

%7D%20" id="TexFormula1" title=" \sqrt[3]{ {x}^{5} } " alt=" \sqrt[3]{ {x}^{5} } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
schepotkina [342]3 years ago
3 0

Answer:

BOTTTTTTTTTTTTTT

Step-by-step explanation:

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sweet [91]
<h3>Answer:  y = 5</h3>

==============================================================

Explanation:

For any rectangle, the diagonals are always the same length. We can use congruent triangles to prove this.

This means AC = BD.

Also, the diagonals of a rectangle cut each other in half (bisect). This indicates the following two equations

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We'll use that second equation along with BP = -2x+23 and DP = 3y-6 to form the equation -2x+23 = 3y-6. This will be used later.

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By the segment addition postulate, we know that

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Equating the two right hand sides leads to the equation 2x+4 = -2x+3y+17

---------------

The conclusion of each the last two sections was the following two equations

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We have two equations and two unknowns. We have enough info to be able to find x and y.

Let's isolate 3y in the first equation

-2x+23 = 3y-6

3y-6 = -2x+23

3y = -2x+23+6

3y = -2x+29

Then we can plug this into the second equation

2x+4 = -2x+3y+17

2x+4 = -2x+(3y)+17

2x+4 = -2x+(-2x+29)+17 .... replace 3y with -2x+29

Now solve for x

2x+4 = -2x+(-2x+29)+17

2x+4 = -2x-2x+29+17

2x+4 = -4x+46

2x+4x = 46-4

6x = 42

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x = 7

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