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Vlad1618 [11]
2 years ago
15

which similar triangle, the ratios of all theee pairs of corresponding sides add never equal true or false

Mathematics
1 answer:
faltersainse [42]2 years ago
4 0

The ratio of all the corresponding sides of the triangle are equal to each other.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Two triangles are said to be similar if they have the same shape and the same corresponding angles.

Also, the ratio of all the corresponding sides of the triangle are equal to each other.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Divide 3 on both sides

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At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 111 keypads is analyzed. Find
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Answer:

The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Let <em>p</em> = the proportion of keypads that pass inspection at a cell phone assembly plant.

The probability that a randomly selected cell phone keypad passes the inspection is, <em>p</em> = 0.77.

A random sample of <em>n</em> = 111 keypads is analyzed.

Then the sampling distribution of \hat p is:

\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})\\\Rightarrow \hat p\sim N (0.77, 0.04)

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:

P(0.72

                             =P(-1.25

Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

8 0
3 years ago
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