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BigorU [14]
3 years ago
7

The volume of geyser 2 is 768000cm³. if 1000 cm³= 1 litre convert the volume of geyser 2 to liters​

Mathematics
1 answer:
polet [3.4K]3 years ago
4 0
<h2>Volume</h2>

The volume of geyser 2 is 768000cm³. if 1000 cm³= 1 litre convert the volume of geyser 2 to liters

- To convert cm to liters divide the volume by 1000

  • \tt {768000cm^3}  \div 1000 =  \green{768  \: litres}

Therefore, 768000 cubic centimeters in liters is 768.

<h3>#CarryOnLearning</h3>
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The pulse rates of 174 randomly selected adult males vary from a low of 39 bpm to a high of 111 bpm. Find the minimum sample siz
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Answer:

a. The sample size is approximately 97 adults

Step-by-step explanation:

The given parameters are;

The number of adults surveyed, n = 174

The lowest value of the pulse rate = 39 bpm

The highest value of the pulse rate = 111 bpm

The level of confidence used for determining the sample size = 90%

The given sample mean = 3 pm of the population mean

a. The range rule of thumb states that the standard deviation is approximately one quarter (1/4) of the range

The range = 111 bpm - 39 bpm = 72 bpm

Therefore, the standard deviation, σ = 72 bpm/4 = 18 bpm

The sample size, 'N', is given as follows;

N = \dfrac{z^2 \cdot p \cdot q}{e^2}

Where;

N = The sample size

z = The confidence level, 90% (z-score at 90% = 1.645)

p·q = σ² = 18² = 324

e² = 3² = 9

N = \dfrac{1.645^2  \times 324}{3^2} = 97.4169

Therefore the appropriate sample size, N ≈ 97 adults.

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3 years ago
This is for today help pls!!!
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Answer:

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Area= 43 units^2

Step-by-step explanation:

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In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
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Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

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or

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