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Pavlova-9 [17]
1 year ago
8

2 4/7 divided by 1 3/6 =

Mathematics
2 answers:
Rudiy271 year ago
7 0

Answer:

Step-by-step explanation:

2,57 divided by 1.5 equals

1.713

Westkost [7]1 year ago
4 0

Answer:

12/7 or 1 5/7

Step-by-step explanation:

to solve this equation you must first make both sides improper fractions

2 4/7 = 18/7

1 3/6 = 9/6

you can then simplify the fractions

18/7 cannot be simplified by 9/6 can

9/6 = 3/2

now we divide

\frac{18}{7} / \frac{3}{2}

when met with a division symbol when dealing with fractions you take the second fraction and flip it (reciprocal)

2/3

and then you multiply it

\frac{18}{7} * \frac{2}{3}

divide 18 and 3 by 3

now multiply

\frac{6}{7} * \frac{2}{1} = \frac{12}{7}

that is your answer

12/7 or 1 5/7

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Natalie is going mountain biking. She can buy a bike for $250 or she can rent a bike for $30 an hour. In both cases, she must al
scZoUnD [109]

Given :

Natalie is going mountain biking. She can buy a bike for $250 or she can rent a bike for $30 an hour.

In both cases, she must also rent a helmet for $5 an hour.

To Find :

Which inequality shows the number of hours Natalie must bike for the cost of buying a bike to be less than renting a bike.

Solution :

Let, after t hours total money required is ( if she rent bike ).

T = 30t.

Money required to purchase bike , M = $250.

For cost of buying a bike to be less than renting a bike :

30t>250\\\\t > \dfrac{25}{3}\ hours\\\\t>8\dfrac{1}{3}\ hours\\\\t>8\ hours \ 20 \ minutes

Hence, this is the required solution.

5 0
3 years ago
What is 10+2p=12+1.5p <br> p=
Allushta [10]

Answer:

p=4

Step-by-step explanation:

5 0
2 years ago
21) Jaquan earns $5 per hour raking leaves. He needs at least $170 to buy a new deo game system. Write an inequality that descri
Anna007 [38]
5x>/170
(WORK SHOWN BELOW)

5 0
2 years ago
The histogram below shows the distribution of times, in minutes, required for 25 rats in an animal behavior experiment to naviga
tino4ka555 [31]

Answer:

c. The <em>median</em> and the IQR <em>(Interquartile range)</em>.

Step-by-step explanation:

Considering the histogram for the distribution of times for this experiment (see the graph below), we can notice that this distribution is skewed positively because of "<em>a few scores creating an elongated tail at the higher end of the distribution</em>" (Urdan, 2005). There is also a probable outlier (an animal that navigates around nine minutes). An outlier is an extreme value that is more than two standard deviations below or above the mean.

In these cases, when we have <em>skewed and extreme</em> <em>values</em> in a distribution, it is better to avoid using the <em>mean and standard deviations</em> as measures of central <em>tendency</em> and <em>dispersion</em>, respectively. Instead, we can use the <em>median</em> and the <em>interquartile range</em> for those measures.

With skewed distributions, the mean is more "sensible" to extreme data than the median, that is, it tends to not represent the most appropriate measure for central position <em>(central tendency)</em> in a distribution since in a positively skewed distribution like the one of the question, the mean is greater than the <em>median</em>, that is, <em>the extreme values tend to pull the mean to them</em>, so the mean tends to not represent a "reliable" measure for the central tendency of all the values of the experiments.

We have to remember that the dispersion measures such as the <em>standard deviation</em> and <em>interquartile range</em>, as well as the <em>variance</em> and <em>range</em>, provide us of measures that tell us <em>how spread the values are in a distribution</em>.

Because the <em>standard deviation depends upon the mean</em>, i.e., to calculate it we need to subtract each value or score from the mean, square the result, divide it by the total number of scores and finally take the square root for it, we have to conclude that with an inappropriate mean, <em>the standard deviation is not a good measure for the dispersion of the data, </em>in this case (a positively skewed distribution).

Since the median represents a central tendency measure in which 50% of the values for distribution falls below and above this value, no matter if the distribution is skewed, the median is the best measure to describe the center of the distribution in this case.

Likewise, the <em>quartiles</em> are not affected by <em>skewness</em>, since they represent values of the distribution for which there is a percentage of data below and above it. For example, the first quartile (which is also the 25th percentile) splits the lowest 25% of the data from the highest 75% of them, and the third quartile, the highest 25%, and the lowest 75%. In other words, those values do not change, no matter the extreme values or skewness.

For these reasons, we can say that the median and the interquartile range (IQR) describe the center and the spread for the distribution presented, and not the most usual measures such as the mean and standard deviation.

5 0
3 years ago
The area of rectangle ABCD is 28 cm^2
Sonbull [250]

The length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4

A rectangle is a quadrilateral in which opposite sides are equal and parallel to each other. The area of a rectangle is:

Area = length * width

From the image:

Length of AB = x + 4

Length of BC = x + 6

The area of rectangle ABCD = Length of AB * Length of BC

28 = (x + 4)(x + 6)

x² + 10x + 24 = 28

x² + 10x = 4

Comparing with x² + ax = b gives:

a = 10, b = 4

Therefore the length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4

Find out more at: brainly.com/question/15019502

8 0
2 years ago
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