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3 years ago

Find (x - 6)2

Mathematics

2 answers:

Sever21 [200]3 years ago

7 0

Its 4-6=2 its easy because just keep useing numbers until the become two

IRISSAK [1]3 years ago

5 0

The answer is b if the question is (x-6)^2 and NOT (x-6)2

(x-6)^2= 2x +12x +36

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Which ordered pair is a solution of this

Stells [14]

Answer:

(-1,-2)

Step-by-step explanation:

I graphed the equation on the graph below so you can see that (-1,-2) is a solution.

6 0

3 years ago

NEED HELP . GIVING BRAINLIEST

andreev551 [17]

Answer:

There are 108 inches in 9 feet

Step-by-step explanation:

Well, two unit multipliers mean we have to convert through two units before we arrive at our final answer so we can convert from feet to yards to inches!

We know that 3 feet equal a yard, right?

So we can divide 9 by 3 to get the amount that 9 feet translates to in yards.

$9/3 = 3!$

So we are now done with our first conversion! Our second is going to be from yards to inches!

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3 years ago

Suppose that x is the probability that a randomly selected person is left handed. The value (1-x) is the probability that the pe

harina [27]

Answer:

The maximum variance is 250.

Step-by-step explanation:

Consider the provided function.

$V(x)=1000x(1-x)$

$V(x)=1000x-1000x^2$

Differentiate the above function as shown:

$V'(x)=1000-2000x$

The double derivative of the provided function is:

$V''(x)=-2000$

To find maximum variance set first derivative equal to 0.

$1000-2000x=0$

$x=\frac{1}{2}$

The double derivative of the function at $x=\frac{1}{2}$ is less than 0.

Therefore, $x=\frac{1}{2}$ is a point of maximum.

Thus the maximum variance is:

$V(x)=1000(\frac{1}{2})-1000{\frac{1}{2}}^2$

$V(x)=250$

Hence, the maximum variance is 250.

4 0

3 years ago

If an orthocenter lies inside of a triangle, then the triangle must be

Black_prince [1.1K]

Answer:

<h2><u><em>acute</em></u></h2>

Step-by-step explanation:

Remember :the orthocenter of a triangle is the point of concurrency of the 3 altitudes.

$\large \text{If an orthocenter lies inside of a triangle, then the triangle must be}\ :\\\\\large isosceles. \\\\\large obtuse. \\\\\large right. \\\\\large acute \checkmark$

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2 years ago

Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (

Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that $I=\int_0^3 x^3-4x dx=9/4$ . We use the properties of integrals to write the new integrals in terms of I.

A) $\int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2$ . We have used that ∫cf dx=c∫f dx.

B) $\int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4$ . Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0

3 years ago