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dusya [7]
2 years ago
10

Pls ANWSER pls pls pls I’ll get brainly

Mathematics
2 answers:
Charra [1.4K]2 years ago
7 0

Answer:

C

Step-by-step explanation:

Its C

frutty [35]2 years ago
6 0

Answer:

50 miles per hour

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Determine if the statement is true or false. If a linear system has the same number of equations and variables, then it must hav
lutik1710 [3]

Answer:

False

Step-by-step explanation:

Consider the equations with the same number of equations and variables as shown below,

<u>Case 1</u>

                        x_{1} + x_{2} = 0\\x_{1} + x_{2} = 1

This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.

<u>Case 2</u>

                       x_{1} + x_{2} = 1\\2x_{1} + 2x_{2} = 2

This equation has infinitely many possible solutions.

Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.

5 0
3 years ago
The endpoints of the longest chord on a circle are (4, 5.5) and (4, 10.5).the center of the circle is at the point , and its rad
Furkat [3]
 The midpoint of the points ( 4, 5.5 ) and ( 4, 10.5 ) is the center of the circle:
 C =(\frac{4+4}{2}, \frac{5.5+10.5}{2})
 C = ( 4, 8 ),  h=4, k=8
 r =\sqrt{(4-4)^{2} +(8-5.5)^{2} } = \sqrt{0+2.5^{2} }
 r = 2.5
 The equation of the circle in standard form:
 ( x - h )² + ( y - k )² = r²
 ( x - 4 )² + ( y - 8 ) = 6.25    
4 0
3 years ago
Read 2 more answers
Vinnie drives his car 210 miles and has an average of a certain speed. If the average speed had been 3mph more, he could have tr
Pachacha [2.7K]

Answer:

35 mph

Step-by-step explanation:

time = distance / speed

210 miles and has an average of a certain speed

t = 210 / s

If the average speed had been 3mph more, he could have traveled 228 miles in the same length of time

t = 228 / (s + 3)

Set equal

210 / s = 228 / (s + 3)

Cross multiply

210s + 630 = 228s

Subtract 210s from both sides

630 = 18s

Divie both sides by 18

35 = s

35 mph

5 0
3 years ago
Read 2 more answers
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
What do we do to both sides of this equation to solve?
allsm [11]

Answer:

Subtract 3 from both sides.

Step-by-step explanation:

x + 3 = 5

x = 5 - 3

<u>x = 2</u>

I know I`m late sorry, still wanted to answer

. _ .

3 0
2 years ago
Read 2 more answers
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