- The name of the circle is <u>IJKL</u>
- The name of central Angle
- The name of the secant = <u>KL</u>
Circle :- It is a round figures, which has no end points.
Central angle :- It the angle ,which lie in the middle of the circle.
- Here, H is the mid point of the circle .So, Angle IHJ is the central angle.
Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .
- Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.
- Semicircle = FGH and FIH
- Minor Arc :- FG or GH
- Major Arc :- FHG or GFH
Semicircle :- Semicircle is nothing but the half of the circle.
<u>Here</u><u>, </u><u>In </u><u>second </u><u>diagram </u>
- FGH and FIH are acting as two semicircles which simulatineously forming one circle.
Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FG or GH are the minor arc of the given circle.
Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FHG or GFH is the major arc as it is larger than the semicircle of the given circle .
To find the length of the ladder, you need to do Pythagorean theorem.
50^2 + 30^2 = x^2
2500 + 900 = x^2
x^2 =3400
x= square root of 3400
58.31 OR 10 root34
To find the angle:
tan theta = opposite/adjacent
50/30 = 5/3
theta = tan inverse of 5/3
= 59.04
It’s letter C.
If you start at point (0,0) and go up two over one (rise over run) to the left, you’ll be at (-1,2). Go up two over one again to the left to get to (-2,4). Your equation would be: y=-2x+0 (0 because you started at 0 so your y-intercept is 0) though since it’s +0 you can leave that out and have y=-2x. It’s a negative slope because the line would be going down to the right.
Answer:
Triangle AEC can be proved congruent to triangle BED by St= 8x2 .
Step-by-step explanation:
