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dedylja [7]
1 year ago
10

What is the equation of the line that passes through point(7, -8) and has a slope of zero? A. y =7B. x = 7C. x = -8D. y = -8

Mathematics
1 answer:
Bond [772]1 year ago
6 0

y = -8

y = mx + b, where m is the slope and b is the y intercept

since m = 0, the term mx = 0

since the line passes throug (7, -8) then y = -8

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Step-by-step explanation:

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A fraction with a numerator of 1 is called a _ fraction
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Unit fraction

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
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Step-by-step explanation:

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a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

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a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

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a'(a(d)) = a'(5d - 3)

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Add fractions

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a(a'(d)) = a'(a(d)) = d

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