3 years ago

Ax+by=c solve for y plz help hurryyyyy

Mathematics

1 answer:

Leviafan [203]3 years ago

5 0

I believe that the answer for y is...

y= -ax+c/b

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Evaluate the expression for the given values.<br><br> 2x + (3y + z2)<br> X = 2, y = 3, z = 4

bazaltina [42]

Answer:

Step-by-step explanation:

2(2)+(3(3)+(4²))

4+(9+16)

4+25

pls if this was h helpful pls tag brainiest

3 0

2 years ago

The graphs of f(x) and g(x) are shown below:

rosijanka [135]

<h2>Answer:</h2>

Option: C is the correct answer.

C.) x = −3.8, 3

<h2>Step-by-step explanation:</h2>

The function f(x) is given by:

$f(x)=x^2-x-12$

and the function g(x) is given by:

$g(x)=-1.8x-0.6$

Now, we are asked to find the solution of the equation:

$f(x)=g(x)$

i.e. we have to find the value of x such that both the functions are equal i.e.

$x^2-x-12=-1.8x-0.6\\\\i.e.\\\\x^2-x+1.8x-12+0.6=0\\\\i.e.\\\\x^2+0.8x-11.4=0\\\\i.e.\\\\10x^2+8x-114=0\\\\i.e.\\\\5x^2+4x-57=0$

Now, on solving the equation using the quadratic formula i.e. the solution of the equation:

$ax^2+bx+c=0$

is given by:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have:

$a=5,\ b=4\ and\ c=-57$

Hence, the solution is given by:

$x=\dfrac{-4\pm \sqrt{4^2-4\times 5\times (-57)}}{2\times 5}\\\\i.e.\\\\x=\dfrac{-4\pm \sqrt{16+1140}}{10}\\\\i.e.\\\\x=-3.8\ and\ x=3$

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3 years ago

A train travels 3.5 kilometers on a straight track with grade of 1 degree 10'. What is the vertical rise of the train distance?

denpristay [2]

The answer is
h = AB sin tetha,
tetha is <span>1 degree 10' = 1.1°, and AB = 3.5km

the vertical rise is h = 4.7</span>

3 0

3 years ago

What is 5/16 x 246/1000

rosijanka [135]

Fraction form 41/400
decimal form .1025

8 0

2 years ago

PLZZZZ HELPPPP !!!!!

Irina-Kira [14]

5 to -4 is your answer

3 0

2 years ago

Read 2 more answers