The mean exists at 3 and the standard deviation exists 0.87.
Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:
<h3>What is the binomial probability distribution?</h3>
The expected value of the binomial distribution exists:
The standard deviation of the binomial distribution exists:
In this problem, the proportion and the sample size exist given as follows:
p = 0.75
n = 4
Therefore, the mean and the standard deviation exist given by:
The mean exists at 3 and the standard deviation exists 0.87.
To learn about the binomial distribution refer to:
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Answer:
(m + 3) (m - 6)
Step-by-step explanation:
Simplify the following:
m^2 - 3 m - 18
The factors of -18 that sum to -3 are 3 and -6. So, m^2 - 3 m - 18 = (m + 3) (m - 6):
Answer: |
| (m + 3) (m - 6)
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3/5 + 5/7 = 1 11/35 - 1/5 = 1 4/35 which is your final answer.
Answer:
A = (Z-CD - EFG)/B
Step-by-step explanation:
AB + CD + EFG = Z.
Subtract CD and EFG from each side
AB + CD + EFG-CD -EFG = Z-CD - EFG
AB = Z-CD - EFG
Divide each side by B
AB /B = (Z-CD - EFG)/B
A = (Z-CD - EFG)/B
