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inn [45]
1 year ago
6

A slope of − 2that goes through the point (–3, 7).! And show work please!

Mathematics
2 answers:
lara [203]1 year ago
7 0

y= mx + c

replace

7=-2(-3) + c

c= 1

y=-2x +1

melisa1 [442]1 year ago
6 0

Answer:

y=-2x+1

Step-by-step explanation:

y=mx+b is the slope intercept form where m is the slope and b is the y intercept

To find b we fill in all the values we know

7=-2(-3)+b

7=6+b

-6 -6

1=b

The equation is now y=-2x+1

Hopes this helps please mark brainliest

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Please solve and show all steps and work
pshichka [43]
Solve the rational equation by combining expressions and insulating the variable X .
all real numbers .
5 0
3 years ago
Find the slope of the line that contains the following ordered pairs. Show all work.
Yakvenalex [24]

Answer:

see below

Step-by-step explanation:

slope = (y₂ - y₁) / (x₂ - x₁)                 <=== formula

         = (2 - (-7)) / (18 - 18)

         = 9 / 0

         = 0                                         <=== slope

6 0
3 years ago
A ramp 18 ft long rises to a platform. The bottom of the platform is 13 ft from the foot of the ramp. Find x, the angle of eleva
Varvara68 [4.7K]

Answer:

The answer to your question is: Ф = 43.95°

Step-by-step explanation:

Data

length = 18 ft

distance bottom to is 13 ft

x = angle = ?

Formula

cos Ф = opposite side / hypotenuse  

Process

cos Ф = 13 ft / 18 ft                   substitution

cos Ф = 0.72                            simplify

Ф = cos⁻¹ (0.72)

Ф = 43.95°                                result

8 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
Nikolay [14]

8²

(8^3)(8^-2)(8^1)

=512(8^-2)(8^1)

=512(1/64)(8^1)

=8(8^1)

=(8)(8)

=64

√64=8

(8•8 so 8²)

4 0
2 years ago
Read 2 more answers
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
3 years ago
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