Answer: 3.751*10^18kg
Step-by-step explanation:
δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.
Calculating the density of air at 5km above earth surface
P = 5000m + 6370000m = 6.375*10^6m
δ = 619.09 -(.000097* 6.375*10^6)
δ = 0.715kg/m^3 = density
Since Mass = density*volume...equ2
To calculate volume of air around the spherical earth at height 5km
V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6
Substituting R and r in equation 2 to solve for volume of air
V = 1.085*10^21 - 1.08*10^21
V = 5.25*10^18m^3
Substituting δ and V into equation 2 to solve for mass of air
M = 0.715 * (5.25*10^18)
M = 3.751*10^18kg
Answer:
dmdy u ymjyforibetbrylnryikbee
Answer:
<h2><u><em>
2.74 m</em></u></h2>
Step-by-step explanation:
<u><em>convert to meters</em></u>
6 dm = 0.6 m
40 mm = 0.04 m
2 m = 2 m
10 cm = 0.1 m
sum
0.6 + 0.04 + 2 + 0.1 =
2.74 m
L think number 6 is a positive slope
What lesson are you working on ? because there are different formulas to find the solutions for a triangle
