What is the first step when rewriting y = 6x2 18x 14 in the form y = a(x

Need help doing this, please show steps. :)

Pavel [41]

Answer:

75.02 ft

Step-by-step explanation:

Split the problem into 2 different part. The bottom part of the tree is 5 feet because that's where your eye levels are, so you just have to solve the top part of the tree.

The top part of the tree is solved by finding the height of the triangle. If you remember SohCahToa, the opposite side of the angle is solved using tangent.

tan(angle) = opposite/adjacent

tan(35) = x/100, x is just the unknown height of the tree.

multiply 100 on both side to get x by itself.

x = 100tan(35)

x = 70.02

add that top height of the tree(70.02ft) with the bottom height of the tree(5ft).

70.02+5 = 75.02 ft

6 0

2 years ago

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The following table shows the number of internet users in 2012 for the highest using countries.

Arisa [49]

The median is 152 internet users :)

8 0

3 years ago

The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (-1,8). The ball reache

ddd [48]

Answer:

Let's suppose that the hole is at y = 0m, where x is the time variable.

we know that:

The vertex is (-1s, 8m).

(i suppose x in seconds and y in meters)

At x = 1s, the ball reaches the hole, so we also have the point:

(1s, 0m).

Remember that the vertex of a quadratic equation y = a*x^2 + b*x + c is at:

x = -b/2a,

then we have:

-1 = -b/2a.

Then we have tree equations:

8m = a*(-1s)^2 + b*-1s + c

0m = a*(1s)^2 + b*1s + c

-1s = -b/2a.

First we should isolate one variable in the third equation, and then replace it in one of the other two:

1s*2a = b.

So we can replace b in the first two equations bi 1s*2a.

8m = a*1s^2 - 1s*2a*1s + c

0m = a*1s^2 + 1s*2a*1s + c

We can simplify both equations and get:

8m = a*( 1s^2 - 2s^2) + c = -a*1s^2 + c.

0m = a*(1s^2 + 2s^2) + c = a*3s^2 + c.

Easily we can isolate c in the second equation and then replace it into the first equation:

c = -a*3s^2

The first equation becomes:

8m = -a*1s^2 - a*3s^2 = -a*4s^2

a = 8m/-4s^2 = -2m/s^2.

Now with a, we can find the values of c and b.

c = -a*3s^2 = -(-2m/s^2)*3s^2 = 6m.

b = 1s*2a = 1s*(-2m/s^2) = -2m/s.

Then the equation is:

y = (-2m/s^2)*t^2 + (-2m/s)*t + 6m

5 0

2 years ago

The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in amb

Zigmanuir [339]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

114, 261, 319, 183,654,313,58,98,335,324,52,125,342,66,321,893,690,798,201,74,632,216,76,155,161,304,530,1110,93,631,75,344,264,1120,122,45,304,192,316,63

USING CALCULATOR :

The mean(m) of the data: = ΣX/n

n = sample size = 40

m = 12974/40

m = 324.4

Median = ((n + 1)/2) th term = 41/2 = (20 + 21)th term / 2

= (261 + 264) / 2 = 262.5

Standard deviation (s) = sqrt(Σ(x - m)²/n))

s = 281. 74

B.) Coefficient of skewness (Ks) :

3(mean - median) / standard deviation

3(324.4 - 262.5) / 281.74

= 0.66

Mild positive skewness Given a positive skew Coefficient value.

(d-1) Are there any outliers?

Yes

Four outliers

(d-2) What are the limits for outliers? (Round your answers to 1 decimal place. Negative amounts should be indicated by a minus sign.)

Lower bound = Q1 - (1.5 * IQR)

Upper bound = Q3 + (1.5 * IQR)

IQR = Q3 - Q1

Q3 = upper quartile = 343 ; Q1 = 106 ; Q2 = 262.5

IQR = 343 - 106 = 237

Lower bound = 106 - (1.5 * 237) = - 249.5

Upper bound = 343 + (1.5 * 237) = 698.5

-249.5 ≤ X ≤ 698.5

4 0

3 years ago

Given the graph below, which of the following statements is true?

Nesterboy [21]

To be a function, it has to pass the vertical line test, which means a vertical line drawn anywhere in the graph should cut the graph only once, not more.

To be a one-to-one function, it has to pass the vertical line test as well as the horizontal line test, which means that a horizontal line drawn anywhere in the graph should cut the graph only once, not more.

Of course, it passes the vertical line test, so its a function.

Does it pass the horizontal line test? NO! As shown in the attached picture, the blue line (horizontal line) cuts the graph at 3 places. We therefore eliminate choices A and B. We can eliminate choice C because nowhere is it required a function to pass through the origin for it to be one-to-one. Hence, the answer is D (blue line shows this).

ANSWER: D

6 0

2 years ago

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What is the first step when rewriting y = 6x2 18x 14 in the form y = a(x – h)2 k?