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trapecia [35]
1 year ago
15

Find the zeros of each functions by using a graph and a table. F(x)=x^2+9x+14

Mathematics
1 answer:
Cloud [144]1 year ago
6 0

Zeroes of a function are the values of x when f(x) = 0

So to find the zeroes of the function from the graph search for the points whose y-coordinates = 0

The y-coordinates of the point = 0, if the points lie on the x-axis

That means the zeroes of the function are the points of intersection between the graph and the x-axis

let us see that in the graph

I will draw it and post it here

From the graph

The graph intersects x-axis at points (-7, 0) and (-2, 0)

Then the zeroes of the function are (-7, 0) and (-2, 0)

Let us make the table

x f(x)

-2 0

-1 6

0 14

1 24

2 36

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stealth61 [152]
I think that maybe 16 is rational
7 0
3 years ago
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7x² + 6x - 1<br> Algebra 3|factoring
GaryK [48]

Answer:

(7 x - 1) (x + 1)

Step-by-step explanation:

Factor the following:

7 x^2 + 6 x - 1

Factor the quadratic 7 x^2 + 6 x - 1. The coefficient of x^2 is 7 and the constant term is -1. The product of 7 and -1 is -7. The factors of -7 which sum to 6 are -1 and 7. So 7 x^2 + 6 x - 1 = 7 x^2 + 7 x - x - 1 = (7 x - 1) + x (7 x - 1):

(7 x - 1) + x (7 x - 1)

Factor 7 x - 1 from (7 x - 1) + x (7 x - 1):

Answer: (7 x - 1) (x + 1)

5 0
4 years ago
i need an equation and i am stuck on this one. there is a pattern but i cant figure out what! help me please!!
natka813 [3]

The equation for this table of values is y=3x-1

3 0
4 years ago
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The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is soli
stiks02 [169]
The first line through points (-3, 0) and (-4, -1) is the orange line.

The second line, through (1, 1) and (2, -1) is the purple line.

Since they are both shaded below, the intersection of the shaded regions, is the region colored in blue.

Both lines are included, since they are solid lines.



The equation of the first line can be found as follows:

the slope is \frac{0-(-1)}{-3-(-4)}=\frac{1}{1}=1, thus, the equation is:
y-0=1(x-(-4))\\\\y=x+4


The equation of the second line can be found as follows:

the slope is \frac{1-(-1)}{1-2}= \frac{2}{-1}=-2, 

thus the equation of the second line is :


y-1=-2(x-1)\\\\y-1=-2x+2\\\\y=-2x+3


We have to decide on the direction of the inequality sign, so we pick a point, for example (0, 4) which is not in the colored regions of the lines, 

so we write the inequalities so that they do not hold for (0, 4)


line 1:

y≥x+4

4≥0+4=4 is true, so we change the sign and write : y≤x+4


similarly, line 2:

y≤-2x+3

4≤-2*0+3=3, which is not true, so we have the correct direction.


Note that since the lines were solid, we include the equality case:


Answer: 

the shaded region is the solution to the system of inequalities:

i) y≤x+4
ii) y≤-2x+3

3 0
3 years ago
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Find the value of p for which the given pair of linear equations have infinitely many solutions for 4X + 3 Y - 4 is equals to ze
tino4ka555 [31]

Answer:

x=8/3

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Step-by-step explanation:

4X + 3Y -4 =0

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x + y = 0

so 4X + 3Y =4

THEN

3X + 9Y = - 12

next use calculator to solve it or you can use traditional way

4 0
4 years ago
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