Answer:
$5.38 per pound
Step-by-step explanation:
70/13=5.384615
5.38x13=69.94
in plain and short, to graph an inequality, we first graph its EQUALITY graph, and then we do the shading.
so to graph y > x + 3, we first graph y = x + 3, which is just a line, and then do a true/false check on a point to see which side we shade.
let's hmmm check the point say (0,2), x = 0, y = 2.
y > x + 3
2 > 0 + 3
2 > 3 <--- is that true? is 2 really larger than 3? nope, so is false.
that simply means that the point (0, 2) is on the false area, so that's the area we do NOT shade, so <u>we shade the other side</u>.
y > x + 3, means "y" is greater than or larger than that line, but not equals, larger not equal, meaning the values on the borderline are not included, so the line is a dashed line.
check the picture below.
Answer:
yeet
Step-by-step explanation:
<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
------------------------
</span>

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>

<span>
-------------------------
</span>

<span>
-------------------------
</span>

<span>
-----------
</span>

<span><span>
</span></span><span>Substitute in equation (I) to find the value of "Y".
</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3

Answer:

Answer:
20,158 cases
Step-by-step explanation:
Let
represent year 2010.
We have been given that since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year.
Since the flu cases decrease to 85% of the prior year, so the flu cases for every next year will be 85% of last year and decay rate is 15%.
We can represent this information in an exponential decay function as:


To find number of cases in 2020, we will substitute
in our decay function as:



Therefore, 20,158 cases will be reported in 2020.