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Ket [755]
3 years ago
6

The basis for an effective evaluation of art is the _____ analysis of the artwork.

Mathematics
1 answer:
horsena [70]3 years ago
4 0

Answer: Visual

Step-by-step explanation:

Visually analyzing the art work is an effective way

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A set of data with a mean of 53, and a standard deviation of 6.2 is normally distributed. Find the value of a data point that is
Evgesh-ka [11]

The value of a data point that is -2 standard deviations from the mean

so, 40.6 to 65.4.

<h3>What is the empirical rule?</h3>

According to the empirical rule, also known as the 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95%, and 99.7% of the values lies within one, two, or three standard deviations of the mean of the distribution.

P(\mu - \sigma < X < \mu + \sigma)  \approx 68\%\\P(\mu - 2\sigma < X < \mu + 2\sigma)  \approx 95\%\\P(\mu - 3\sigma < X < \mu + 3\sigma)  \approx 99.7\%

From the empirical rule, we know that for 95% we are in 2 standard deviations of the mean. so:

= 53- 6.2- 6.2

= 40.6

The value of a data point that is -2 standard deviations from the mean

53 + 6.2 + 6.2

= 65.4

Learn more about the empirical rule here:

brainly.com/question/13676793

#SPJ2

7 0
2 years ago
Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}&#10;\\ \quad \\&#10;\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\&#10;-----------------------------\\\\&#10;\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}&#10;\\\\\\&#10;\textit{now taking }sin^{-1}\textit{ to both sides}&#10;\\\\\\&#10;sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)&#10;\\\\\\&#10;\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
8 0
4 years ago
Isabella worked 50 hours over the past two weeks, and she gets paid by the hour. During the first week of the two-week span, she
4vir4ik [10]

Answer:

$190.00

Step-by-step explanation:

285÷30=9.5

9.5×20=190

Hope this helps! :)

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3 years ago
Simplify the expression the root of negative sixteen all over the quantity of three minus three i plus the quantity of one minus
aliya0001 [1]
The first step is to multiply the fraction by (3 +3i) / (3 +3i) to delete the i terms from the denominator:

\frac{ \sqrt{-16} }{3-3i} . \frac{3+31}{3+3i} +1-2i=  \frac{4i(3+3i)}{9+9} +1-2i= \frac{12i-12}{18} +1-2i=

\frac{12i-12+18-36i}{18} = \frac{6-24i}{18} = \frac{1}{3} - \frac{4}{3} i
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3 years ago
From least to greatest 2.3, 2 4/5, 2.6
algol [13]
2.3, 2.6, 2 4/5

2 4/5= 2.8
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3 years ago
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