For this case what you should do is use the following trigonometric relationship:
tan (x) = C.O / C.A
Where
x: angle
C.O: opposite leg
C.A: adjoining catheto
Substituting the values we have:
tan (60) = long / short
tan (60) = long / 2
long = 2 * tan (60)
long = 3.46
Answer:
long = 3.46
Answer:
speed of motorcycle = 40 mph
speed of car = 50 mph
Step-by-step explanation:
Here is the complete question
A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycle. Find the speed of both the car and the motorcycle, in miles per hour.
Speed = distance / time
This question would be solved using simultaneous equation
let m = average speed of the motorcycle
c = average speed of the car
c = 2m - 30 equation 1
20 =(c - m) x 2 equation 2
insert equation 1 into equation 2 and divide through by 2
10 = (2m - 30) - m
solve for m
m = 40 mph
substitute for m in equation 1
2(40) - 20 = 50 mph
It would be bisecting angles
Answer:
3 * 3 * 3 * 3
=> 
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Answer:
if you make the 3.5 equal 7/2
and the 1.40 equal 7/5 its will be more easier
so7/5 × 7/2 its 4.9
sorry guys its not 4.9 i made mistake with 3.25 i was thinking that it was 3.50 any wwy
i have good method too
we can make 3.25 equal 13/4 and 1.40 equal 7/5 the multiply it
we will find 91/20 but we have problem its The 10 dont worry we can take the 10 from the both number and we will get 9.1/2 and We can devide easily now and the answer is 4.55
sorry iam trying so hard to speak engilish well sorry if u cannot understand me big respet for all the students
