Step-by-step explanation:
calculate the area of the shape(s) on the inside and then the area of the sphape on the outside, then subtract the inside's area from the outside shape. im still working on this one, check back in a bit.
X= square root 10 over 2 minus 3 and negative square root of 10 over 2 minus 3
Answer:
<em>9</em><em>0</em><em> </em><em>degree</em><em> </em><em>EFC</em><em>. </em><em>and</em><em>. </em><em>BMC</em>
<em>across</em><em> </em><em>fc</em><em>/</em><em>ma</em><em> </em>
<em>across</em><em> </em><em>ec</em><em>/</em><em>ab</em>
Answer:
y= -4x-6 is the required equation.
Step-by-step explanation:
Lets take (0,-6) and (1,-10)
now
slope = (y2-y1)/(x2-x1)
= ((-10+6)/(1-0)
= -4/1
so, m = -4
again
y=mx+c
or, -10=-4×1+c
or, -10 = -4+c
so, c = -6
now
y=mx+c
or, y = -4x-6
