Post the map
we need to see α photo in order to answer the question.
Answer:
y=(1/2)x+4
Step-by-step explanation:
Since slope-intercept form is y=mx+b, all we need to do is divide both sides by 2:
2y=x+8
y=1/2x+4
Thus, the equation would be y=1/2x+4
Solve the equation for x by find the A , B , C of the quadratic then applying the quadratic formula
Answer:
y = -3/2 x +13
Step-by-step explanation:
We want our line to be perpendicular to
y = 2/3 x -1
The slope of this line is 2/3 (since it is written in the form y = mx+b and m is the slope)
Perpendicular lines have negative reciprocal slopes
m = -(3/2)
The slope of our new line is -3/2
We can use point slope form of the equation
y-y1 - m (x-x1)
y - 7 = -3/2 (x-4)
Distribute
y-7 = -3/2x +6
Add 7 to each side
y-7+7 = -3/2 x +6+7
y = -3/2 x +13
F(x) = 8 - 10x
g(x) = 5x + 4
Finding (fg)(-2).
First let us find fg(x), this is the same as f(g(x))
f(g(x))
f(5x + 4)
Recall, f(x) = 8 - 10x, therefore f(5x + 4) would be such that anywhere we see x in the f(x), we replace it with 5x + 4
f(x) = 8 - 10x
f(5x +4) = 8 - 10(5x + 4)
= 8 - 50x - 40
= -50x + 8 - 40
= -50x - 32
f(g(x)) = fg(x) = -50x - 32
fg(-2) = -50*(-2) - 32 = 100 - 32 = 68
Therefore fg(-2) = 68
I hope this helped.
