Answer:
Step-by-step explanation:
First, rewrite the given equation in the form of y=mx+c.
m is the gradient while c is the y-intercept.
3x-5y=8
5y= 3x -8
Thus, the gradient of the given equation is ⅗.
The product of the gradients of perpendicular lines is -1.
(gradient of line)(⅗) = -1
gradient of line= -1 ÷⅗
gradient of line=
To find the value of c, substitute a coordinate.
When x=3, y=7,
7= -5 +c
c= 7+5
c= 12
Hence, the equation of the line is .
Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'
